Answer:
1. 125
2. 25
3. 40
4. 39
First question:
(15-10)^2 + (15-5)^2
parentheses first to get 5^2 + (15-5)^2
exponents next to get 25 + (15-5)^2
parentheses again 25 + 10^2
exponents again 25 + 100 = 125
Second question:
simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29
Third question:
simplify in the parentheses 6 1/7 - 1/7 = 6
divide 60 by 6 to get 10
multiply 10 by 4 to get 40!
Fourth question:
simplify the fractions to get 1/3 + 8/3 = 3
multiply the 3 by 13 to get 39
The sum of five and the quotient of two and four
because u do division first
Answer:
No savings
Step-by-step explanation:
Let the interest rate be same for all the loans and consider it to be R.
<u>First case</u>
Principal 1 = 2000
Time = 12 moths =
= 1 year
Rate = R %
So, interest 1 = Principal * Time * Rate
= 2000 * 1 * R
= 2000R
Now,
Principal 2 = 1000
Time = 12 moths =
= 1 year
Rate = R %
So, interest 2 = Principal * Time * Rate
= 1000 * 1 * R
= 1000R
Total interest to be paid = 2000R + 1000R
= 3000R
<u>Second case</u>
Principal = 3000
Time = 12 moths =
= 1 year
Rate = R %
Interest = Principal * Time * Rate
= 3000 * 1 * R
= 3000R
We conclude that there would be no savings because the interest to be paid in both the cases are same.
Answer:
Step-by-step explanation:
let y=ab^x
x=0,y=18
18=ab^0=a
a=18
y=18b^x
when x=2,y=1152

Answer : The duration of the loan is, 6 months
Step-by-step explanation :
First we have to determine the discounted money.
Discounted money = $850 - $800 = $50
Thus, interest = $50
Now we have to determine the time of loan.
Formula used :

where,
P = principle
R = interest rate
T = time
S.I = simple interest
Now put all the given values in the above formula, we get:
For 1 year : 
For 12 months : 

Thus, the duration of the loan is, 6 months