Answer:
Slope=
2.000
0.800
=0.400
x−intercept=
2
/5
=2.50000
y−intercept=
−5
/5
=
−1
1
=−1.00000
Step-by-step explanation:
STEP
1
:
Pulling out like terms
1.1 Pull out like factors :
6x - 15y - 15 = 3 • (2x - 5y - 5)
Equation at the end of step
1
:
STEP
2
:
Equations which are never true
2.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Equation of a Straight Line
2.2 Solve 2x-5y-5 = 0
Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line 2x-5y-5 = 0 and calculate its properties
He payed 0.72
First you take 2.88, then you multiply it by 1/4 or a simpler way would be to divide 2.88 by 4. The answer is $0.72
Answer:
The height is 7 cm
Step-by-step explanation:
210 × 2 = 420
12 × 5 = 60
420 ÷ 60 = 7
Answer:
Step-by-step explanation:
This is an incomplete problem. Other data were not given.
Given:
Profit of every sandwich = $2
Profit of every wrap = $3
x = sandwich
y = wrap
Last month: 2x + 3y = 1,470
Next month: 2x + 3y = 1,593
Based on the given equation:
Both still have the same profit. $2 for sandwiches and $3 for wraps.
The only reason why there is a difference in the total amount is the change in the number of sandwich or wrap sold in a given month.
Since, next month's total sale is higher than last month's total sale, it is safe to assume that the sale of sandwich or wrap is higher than last month's sale.
Answer:
0.2 ; 100 ; 4.84
Step-by-step explanation:
Given that the probability of each of the 5 groups is the same :
Sum of probability = 1
Hence, Probability of each group = 1 / number of groups = 1 / 5 = 0.2
Expected number for each interval for a sample of 500 : ; X = 500
E(X) = X * P(x) = 500 * 0.2 = 100
Goodness of fit (X²) :
X² = Σ(X - E)² ÷ E
Groups :
113, 95, 108, 99, and 85
X : 113 ____ 95 ____ 108 ____ 99 _____ 85
(113 - 100)^2 / 100 = 1.69
(95 - 100)^2 / 100 = 0.25
(108 - 100)^2 / 100 = 0.64
(99 - 100)^2 / 100 = 0.01
(85 - 100)^2 / 100 = 2.25
(1.69 + 0.25 + 0.64 + 0.01 + 2.25) = 4.84
