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Alik [6]
3 years ago
5

I need help please it’s really hard and I don’t understand it

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.

We're told that HJ has length 7<em>x</em> - 27.

The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.

This means we have

7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)

Solve for <em>x</em> :

7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)

7<em>x</em> - 27 = 4<em>x</em> - 6

7<em>x</em> - 4<em>x</em> = 27 - 6

3<em>x</em> = 21

<em>x</em> = 21/3

<em>x</em> = 7

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3 years ago
Find the length of AB
Vlad [161]

Answer:

C. 44.98

Step-by-step explanation:

Hi there!

We are given the right triangle ABC, m<B=12°, and CB =44

We want to find the length of AB

We can use trigonometry to do it

Let's find the ratio in reference to angle B, as that angle is given.

In reference to angle B the opposite angle is AC, the adjacent side is CB, and the hypotenuse is AB

Now let's recall the 3 most commonly used functions:

sine=\frac{opposite}{hypoptenuse}

cosine=\frac{adjacent}{hypotenuse}

tangent=\frac{opposite}{adjacent}

Let's find the cosine of angle B, as it uses CB and AB, which are the given side and the side we need to find

In that case,

cos(12)=\frac{CB}{AB}

cos(12)=\frac{44}{AB}

Multiply both sides by AB

AB*cos(12)=44

Divide both sides by cos(12)

AB=\frac{44}{cos(12)}

Now plug \frac{44}{cos(12)} into your calculator. Make sure your calculator is on degree mode

AB≈44.98

So the answer is C

Hope this helps!

3 0
2 years ago
Find a power series for the function, centered at c. f(x) = 1 9 − x , c = 4 f(x) = [infinity] n = 0 Incorrect: Your answer is in
Wewaii [24]

Looks like the given function is

f(x)=\dfrac1{9-x}

Recall that for |<em>x</em>| < 1, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

We want the series to be centered around x=4, so first we rearrange <em>f(x)</em> :

\dfrac1{9-x}=\dfrac1{5-(x-4)}=\dfrac15\dfrac1{1-\frac{x-4}5}

Then

\dfrac1{9-x}=\displaystyle\frac15\sum_{n=0}^\infty\left(\frac{x-4}5\right)^n

which converges for |(<em>x</em> - 4)/5| < 1, or -1 < <em>x</em> < 9.

4 0
3 years ago
What is the equation of the line that passes through the point (3, -1) and is perpendicular to the equation y = -3x + 2? A. y=-3
LenKa [72]

Answer:

A) y = –3x+8

Step-by-step explanation:

first off, a negative equation means the graph is downward sloping from left to right –> \. So with this in mind you can immediately eliminate C and D because they are upward sloping graphs. B also doesn't work because it doesn't go through (3,–1). This leaves A as the right answer

the constant number is the number on the y-axis. So, for –3x+2, +2 is the y-coordinate on the y-axis. the slope is -3x meaning down 3, right 1. –3x+8 is the only answer that is perpendicular.

4 0
1 year ago
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