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enot [183]
4 years ago
8

Use the coordinates of the labeled point to find the point-slope equation of the line.

Mathematics
2 answers:
LenKa [72]4 years ago
6 0

For this case we have that by definition, the equation of a line of the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}): It is a point through which the line passes

To find the slope, we need two points through which the line passes, observing the image we have:

(x_ {1}, y_ {1}): (3, -5)\\(x_ {2}, y_ {2}): (0,4)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {4 - (- 5)} {0-3} = \frac {4 + 5} {-3} = \frac {9} {- 3} = - 3

Thus, the equation is of the form:

y-y_ {0} = - 3 (x-x_ {0})

We choose a point:

(x_{0}, y_ {0}) :( 3, -5)

Finally, the equation is:

y - (- 5) = - 3 (x-3)\\y + 5 = -3 (x-3)

Answer:

y + 5 = -3 (x-3)

Option D

irina [24]4 years ago
3 0

Answer:

y + 5 = -3 (x-3)

Option D

Step-by-step explanation:

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Anika [276]

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Step-by-step explanation:

If you have a square of side l, its diagonal would be l\sqrt{2}, and its area l^2

If the big square has a area of 900, this implies that its side is \sqrt{900}, so the two diagonal of squares 2 and 4 added together would be \sqrt{900}, therefore one diagonal wold be \frac{\sqrt{900}}{2}. and its side \frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}. The area (of one square) is (\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}

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frosja888 [35]

Answer:

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What is 10x+9-6x=-1?
Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

ok

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