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Elan Coil [88]
3 years ago
10

Did I do this right? What can I fix?

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
It looks right to me!!
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What is 26/15 as a whole number?
Contact [7]

Answer:

1 11/15

Step-by-step explanation:

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2 years ago
Laura picked a crayon randomly from a box, recorded the color, and then placed it back in the box. She repeated the process and
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The answer is B. The next crayon Laura picks is NOT red.
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3 years ago
The figure shows a square, a regular pentagon and a regular hexagon put together. What is the measure of ∠BAC
Elan Coil [88]

Answer:

42

Step-by-step explanation:

One angle of a regular pentagon = 108°

One angle of a regular hexagon = 120°.

One angle of a square = 90°

∴ ∠BAC = 360 – (108 + 20 + 90) 360 – 318 = 42°

8 0
2 years ago
Please help asap!!!
sp2606 [1]

Answer:

y=\frac{1}{6} (x+5)^2-4.5

y=\frac{-1}{20} (x-10)^2+1

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3  and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5  and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

(x+5)^2= 4(1.5) (y+4.5)

(x+5)^2= 6(y+4.5)

divide by 6 on both sides

then subtract 4.5 on both sides

y=\frac{1}{6} (x+5)^2-4.5

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

y=\frac{-1}{20} (x-10)^2+1


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3 years ago
Jamie rented a canoe while she was on vacation. She paid a flat $85.00 plus $7.50 each day. Her total cost was $130.00. For how
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She rented the canoe for 6 days.
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