The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Two Consecutive Odd Numbers: D, D+2
(D+2) + 2D = 4D - 27
D + 2 + 2D = 4D - 27
3D + 2 = 4D - 27
3D + 29 = 4D
29 = D
Two Consecutive Odd Numbers are 29, 31
Check. . 31 + 2(29) = 4(29) - 27
..................31 + 58 = 116 - 27
.................89 = 89 ..... CORRECT!
Answer:
OOOPS-
Step-by-step explanation:
i feel kinda bad stealing your points l-mao
3/5 of the total responses expected = 87...
3/5x = 87
x = 87 / (3/5)
x = 87 * 5/3
x = 435/3
x = 145 <=== what was expected