3) subtract the second equation from the first...
(x+7y=64)
-(x+3y=28)
_________
4y=36 divide both sides by 4
y=9, which makes x+7y=64 become:
x+63=64
x=1
So the solution to the system of equations is the point (1,9)
4)
Subtract the second from the first:
4x-4y=24
-(x-4y=3)
_______
3x=21 divide both sides by 3
x=7, which makes x-4y=3 become:
7-4y=3
-4y=-4
y=1
So the solution to the system of equation is the point (7,1)
Answer:
20hours
Step-by-step explanation:
Old Job hours = 54 -34 = 20 hours
So here is how we are going to solve the problem.
Let C be the cost of the chicken, and D as the cost of the duck.
The equation would be like this:
50c + 30d = 550 (divide this by 10)
5c + 3d = 55
3d = 55 - 5c (multiply by 3)
9d = 165 - 15c
Next,
44c + 36d = 532 (divide this by 4)
11c + 9d = 133
Now, substitute the value of 9d and it becomes
11c + 165 - 15c = 133
11c - 15c = 133 - 165
-4c = -32 (divide by -4)
c = 8
Therefore, the cost of each chicken is $8.00
Now going back to d,
9d = 165 - 15c (substitute c)
9d = 165 - 15(8)
9d = 165 - 120
9d = 45 (divide by 9)
d = 5
So the cost per duck is $5.00
Hope this helps.
Answer:
1.What is the theoretical probability that a coin toss results in two heads showing?
33%
2.What is the experimental probability that a coin toss results in two heads showing?
25%
3.What is the theoretical probability that a coin toss results in two tails showing?
33%
4.What is the experimental probability that a coin toss results in two tails showing?
21%
5.What is the theoretical probability that a coin toss results in one head and one tail showing?
33%
6.What is the experimental probability that a coin toss results in one head and one tail showing?
54%
Step-by-step explanation:
Hope this helps, I just finished my assingmnet like this tonight :))
Answer:
Option D
Step-by-step explanation:
A type I error occurs when you reject the null hypothesis when it is actually true.
The null hypothesis in this case is minimum breaking strength is less than or equal to 0.5.
A type one error would be allowing the production process to continue when the true breaking strength is below specifications.