Answer:
y = 6
Step-by-step explanation:
We have to consider the equation of a line ( in slope - intercept form ) that is parallel to y = 3, and passes through the point ( 0, 6 ). Now y = 3 can be plotted as a horizontal line that passes through the point ( 0, 3 ). If we want a line that is parallel to this, it must be horizontal as well;
Let us consider the second point now. This line must pass through the point ( 0, 6 ). We can conclude that the line must be 1. Horizontal, and 2. Pass through point ( 0, 6 );
Equation - y = 6
Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
56.57
Explanation:
In the process,
Diameter= 18,
Radius(r)=
18
2
∴
Radius= 9
Now,
Circumference (Perimeter) = ?
According to the formula,
Perimeter= 2
×
22
7
×
r
Taking the equation,
Perimeter= 2
×
22
7
×
r
2
×
22
7
×
9
396
7
56.57142857
56.57
Let's hope this helps you:)
So if p then q
the converse is if q then p
so
if x is odd then 2x+1 is odd
converse is
if 2x+1 is odd, then x is odd
4th option
