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Lena [83]
3 years ago
13

Who can help me with this algebra thanks for your help guys.

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

30. 25÷5 = 10÷2

31. 3×3 = 6+3

33. 13+19 = 8×4

34. 14-2 = 6×2

Step-by-step explanation:


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What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest​
natali 33 [55]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}

  • ⇢ Principle = Rs.4000
  • ⇢ Rate = 6%
  • ⇢ Time = 3 year

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}

  • ⇢ Amount

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}

{\dag{\underline{\boxed{\sf{Amount  ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}

\dag{\underline{\boxed{\sf{Compound \: Interest = Amount- Principle }}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Solution:}}}}}}}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{Firstly,Finding  \: the  \: Amount }}}}}}

\quad {:\implies{\sf{Amount  = \bf{P{\bigg(1  +  \dfrac{R}{100}{\bigg)}^{T}}}}}}

  • Substituting the values

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1 \times 100  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{100 + 6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{106}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg({\cancel{\dfrac{106}{100}}{\bigg)}}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{148877}{125000}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000 \times  \dfrac{148877}{125000}}}}}

\quad {:\implies{\sf{Amount  = \bf{4{\cancel{000}} \times  \dfrac{148877}{125{\cancel{000}}}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{148877 \times 4}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{595508}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\cancel{\dfrac{595508}{125}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Amount = {Rs.4764.064}}}}}}}\end{gathered}

  • Hence, The Amount is Rs.4764.064

\begin{gathered}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{ Now,Finding  \: The \:  Compound \:  Interest }}}}}}

\quad{: \implies{\sf{Compound \: Interest =  \bf{Amount- Principle }}}}

  • Substituting the values

\quad{: \implies{\sf{Compound \: Interest = \bf{4764.064- 4000 }}}}

\quad{: \implies{\sf{Compound \: Interest =\bf{764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Compound Interest  = Rs.764.064}}}}}}\end{gathered}

  • Henceforth,The Compound Interest is Rs.764064

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Learn More:}}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
I need help please help
monitta

Answer:

with wut XD

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Help with my geometry homework pleaseeee
anastassius [24]

Answer:

y=1, x=1

Step-by-step explanation:

This is a 90-45-45 triangle. One side is a sq root 2, and the other sides are a and a.

For example, if one side was 3 sq root two, then the other sides would be 3 and 3

6 0
3 years ago
100 POINTS! I WILL GIVE BRAINLIEST! SHOW ALL WORK PLEASE!
pishuonlain [190]

Answer:

1. 2(3x−2)(2x−3)

2. 3(3x+1)(2x+5)

3. 2(4x+1)(2x−5)

4. 4(2x+1)(2x+7)

5. 5(3x+1)(2x−5)

6. 3(3x−7)(2x+1)

7. 3(5x+3)(3x−2)

8. 2(7x−2)(2x−5)

9. 2(7x−3)(2x−3)

10. 4(5x−11)(2x+1)

11. 5(x−2)(x+12)

12. (x−1)(x−8)

15. x=1 or x=4

Step-by-step explanation:

1. Factor 12x2−26x+12

12x2−26x+12

=2(3x−2)(2x−3)

2. 3(3x+1)(2x+5)

3. Factor 16x2−36x−10

16x2−36x−10

=2(4x+1)(2x−5)

4. Factor 16x2+64x+28

16x2+64x+28

=4(2x+1)(2x+7)

5. Factor 30x2−65x−25

30x2−65x−25

=5(3x+1)(2x−5)

6. Factor 18x2−33x−21

18x2−33x−21

=3(3x−7)(2x+1)

7. Factor 45x2−3x−18

45x2−3x−18

=3(5x+3)(3x−2)

8. Factor 28x2−78x+20

28x2−78x+20

=2(7x−2)(2x−5)

9. Factor 28x2−54x+18

28x2−54x+18

=2(7x−3)(2x−3)

10. Factor 40x2−68x−44

40x2−68x−44

=4(5x−11)(2x+1)

11. Factor 5x2+50x−120

5x2+50x−120

=5(x−2)(x+12)

12. Let's factor x2−9x+8

x2−9x+8

The middle number is -9 and the last number is 8.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -9

Multiply together to get 8

Can you think of the two numbers?

Try -1 and -8:

-1+-8 = -9

-1*-8 = 8

Fill in the blanks in

(x+_)(x+_)

with -1 and -8 to get...

(x-1)(x-8)

15. Let's solve your equation step-by-step.

(x−2)(x−3)=2

Step 1: Simplify both sides of the equation.

x2−5x+6=2

Step 2: Subtract 2 from both sides.

x2−5x+6−2=2−2

x2−5x+4=0

Step 3: Factor left side of equation.

(x−1)(x−4)=0

Step 4: Set factors equal to 0.

x−1=0 or x−4=0

x=1 or x=4

Sorry I wasn't able to do 13 and 14 but hope this helps! :)

8 0
3 years ago
Complete the series 1.5, 2.3, 3.1, 3.9, whats next
rusak2 [61]

4.7


Each term is 0.8 bigger than the previous one.

4 0
2 years ago
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