The IQR of the first period is 15. The IQR of the third period is 1/3 that, 5*(1/3) is equal to 5.
For the third period, Q1 is 78. The expression for Q3 is Q1+IQR
Therefore, 78+5 = 83
Q3 of the third period is 83
Answer:
We consider a triangle ABC as attached in the answer.
We draw a line parallel to AB that passes through point C.
Angles C and C' are vertical angles, therefore ∠C = ∠C'.
Angles B and B' are corresponding angles, therefore ∠B = ∠B'.
Angles A and A' are corresponding angles, therefore ∠A = ∠A'.
it can be seen that angle sum ∠A + ∠B + ∠C is equal to the angle sum ∠A' + ∠B' + ∠C'.
The three angles A', B', and C' form together a straight angle so, their angle sum is 180°. But then the angle sum ∠A + ∠B + ∠C must also be 180°.
This proofs that sum of angles of a triangle is equal to 180.
Since you're only interested in x, you can use the first equation to write an expression for y that can be substituted into the second equation.
.. y = k -x
.. 2x +3(k -x) = k +1
.. -x +3k = k +1 . . . . . collect terms
.. 2k -1 -x = 0 . . . . . . subtract k+1
.. 2k -1 = x . . . . . . . . .add x
The 3rd selection is appropriate.
Answer:
It should be red or green 125 times
Step-by-step explanation:
The first thing to do here is to calculate the probability of selecting a red or a green marble
Total number of marbles = 7 + 3 + 2 + 8 = 20
Probability of selecting a red marble is 7/20
Probability of selecting a green marble is 3/20
The probability of selecting a red or a green marble = Probability of selecting a red marble + Probability of selecting a green marble = 7/20 + 3/20 = 10/20 = 1/2
Now our selection spans 250 times, the number of times it should have been a green or a red marble = The probability of selecting a green or a red marble * number of selection times = 1/2 * 250 = 125 times
Answer:
68
Step-by-step explanation:
Any function is evaluated by putting the argument value where the variable is, then doing the arithmetic. When the argument is another function value, that function value is evaluated first.
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<h3>f∘g</h3>
The "o" in (fog) is a stand-in for the "ring operator" (∘) which is the operator used to signify a composition. A composition is evaluated right-to-left. That means (f∘g)(x) ≡ f(g(x)). The value of g(x) is found first, and is operated on by the function f.
Writing the composition in the form f(g(x)) lets you identify the layers of parentheses. As with any expression evaluation, the Order of Operations applies. It tells you to evaluate the expression in the innermost parentheses and work your way out.
<h3>g(-2)</h3>
To evaluate (f∘g)(-2) = f(g(-2)), we must first evaluate g(-2). That is ...
g(x) = 5x +4
g(-2) = 5(-2) +4 = -10 +4 = -6 . . . . . put -2 where x is, do the math
<h3>f(g(-2))</h3>
Now that we know g(-2) = -6, we know this expression is ...
f(-6) = 8 -10(-6) = 8 +60 = 68 . . . . . substitute for x in 8-10x
Then the value we're looking for is ...
(f∘g)(-2) = 68