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Feliz [49]
3 years ago
13

Pete challenges his friend Jill to find two consecutive odd integers that have the following relationship. The product of the in

tegers is 3 times the sum of the integers plus 6. Determine if it is possible to find two such integers.
Mathematics
2 answers:
o-na [289]3 years ago
5 0
2n+1, 2n+3 - consecutive odd integers

(2n+1)(2n+3)=3(2n+1+2n+3)+6\\
4n^2+6n+2n+3=3(4n+4)+6\\
4n^2+8n+3=12n+12+6\\
4n^2-4n+15=0\\
\Delta=(-4)^2-4\cdot4\cdot15=16-240=-224\\

\Delta

It's not possible.
lesantik [10]3 years ago
3 0

I don't think it is.

If the first integer is 'x', then the second one is (x+2).
Their product is (x²+2x), and their sum is (2x+2).

You have said that  (x²+2x) = 3(2x+2) + 6

                                 x²+2x = 6x + 6 + 6

                                 <u>x² - 4x - 12 = 0</u>

                                (x - 6) (x + 2) = 0

                             x = 6    and    x = -2

The numbers are  ('6' and '8'), or ('-2' and 0).

I honestly don't know what to make of the second pair.
But the first pair satisfies the description:

              The product (48) = 3 x the sum (3 x 14 = 42) plus 6.

So '6' and '8' completely work, except that they're not <u>odd</u> integers.


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jekas [21]
All except dilation

Mark brainliest please
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2 years ago
What is the value of m, if the equation my2+2y−4=0 has exactly one root?
stich3 [128]

Answer:

m=\frac{-1}{4}

Step-by-step explanation:

A quadratic equation has one root if the discriminant is 0.

That is we need b^2-4ac=0 for this particular question.

Compare the following to find a,b, \text{ and } c:

ax^2+bx+c=0

my^2+2y-4=0

The variable x is representative of the variable y here.

a=m

b=2

c=-4

Plug in into b^2-4ac=0:

(2)^2-4(m)(-4)=0

4+16m=0

Subtract 4 on both sides:

16m=-4

Divide both sides by 16:

m=\frac{-4}{16}

Reduce:

m=\frac{-1}{4}

6 0
2 years ago
Read 2 more answers
IS 419.10 GREATER THAN 419.099
marysya [2.9K]
Yes, by 0.001. Thank me later.
8 0
3 years ago
Read 2 more answers
A group of friends wants to go to the amusement
Zepler [3.9K]

Answer:

The maximum amount of people that can go to the amusement park is 15.

Step-by-step explanation:

First you create an equation to represent the question

8.75+25.75x≤420

You put the less than or equal to sign because 420 is the maximum amount of money.

Now you just solve the equation.

25.75x≤420-8.75

25.75x≤411.25

x≤411.25/25.75

x≤15.9708738

Then you have to round down because you cant have .9 of a person.

So x≤15

Then, Check your solution

8.75+(25.75 x 15)≤420

8.75+386.25≤420

395≤420

That is true. But to make sure that is the maximum add another 25.75

395+25.75≤420

420.75≤420

This is equation is false so, our answer is correct.

The maximum amount of people that can go to the amusement park is 15.

5 0
1 year ago
BRAINLIEST FOR WHOEVER ANSWERS FIRST!!!!
Fofino [41]

Answer:

x = 34

Step-by-step explanation:

ΔABD and ΔBCD are both isosceles triangles

In ΔABD

AB =AD, hence ∠ABD = ∠ADB ( base angles are equal )

∠ABD = \frac{180-44}{2} = \frac{136}{2} = 68°

∠DBC = 180° - 68° = 112° ( straight angle )

∠BCD = x = \frac{180-112}{2} = \frac{68}{2} = 34


4 0
3 years ago
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