Pete challenges his friend Jill to find two consecutive odd integers that have the following relationship. The product of the in tegers is 3 times the sum of the integers plus 6. Determine if it is possible to find two such integers.
2 answers:
2n+1, 2n+3 - consecutive odd integers
It's not possible.
I don't think it is. If the first integer is 'x', then the second one is (x+2). Their product is (x²+2x), and their sum is (2x+2). You have said that (x²+2x) = 3(2x+2) + 6 x²+2x = 6x + 6 + 6 <u>x² - 4x - 12 = 0</u> (x - 6) (x + 2) = 0 x = 6 and x = -2 The numbers are ('6' and '8'), or ('-2' and 0). I honestly don't know what to make of the second pair. But the first pair satisfies the description: The product (48) = 3 x the sum (3 x 14 = 42) plus 6. So '6' and '8' completely work, except that they're not <u>odd</u> integers.
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