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Naily [24]
3 years ago
6

Ralph sold brownies for ​$0.30

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0
<span>.99(15) = 1.35x 14.85 = 1.35x 14.85/1.35 = 11
 
I think it is 15. I am not sure about the proper way to solve this....I just know that if he sold 15 brownies, he could buy 11 packs with exactly no change left over.</span>
Vilka [71]3 years ago
3 0
The answer is 18, the only way to do this is guess and check and youll find after doing so the .54 cents for the pack times 10 to get 5.4 is the first nukber that evenly divides into .3 which would give you 18 brownies he would have to sell to buy 10 packs of card
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Given the replacement set { 0, 1, 2, 3, 4 }, solve 8x – 6 = 10. x = 0 x = 4 x = 2 x = 3
leonid [27]
The answer is x = 2 because 8(2) is 16 and 16 - 6 = 10
3 0
4 years ago
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Suppose that A and B are nonsingular matrices. Then AB is also nonsingular. Furthermore, a theorem from linear algebra then stat
kherson [118]

Answer:

A) Verified

B) Proved

Step-by-step explanation:

a) Let's verify it for 2 x 2 matrix,

A=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] and B=\left[\begin{array}{ccc}e&f\\g&h\end{array}\right]

AB=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\left[\begin{array}{ccc}e&f\\g&h\end{array}\right]=\left[\begin{array}{ccc}a.e+b.g&a.f+b.h\\c.e+d.g&c.f+d.h\end{array}\right]

(AB)^{-1}=\frac{1}{(a.e+b.g)(c.f+d.h)-(a.f+b.h)(c.e+d.g)}\left[\begin{array}{ccc}c.f+d.h&-(a.f+b.h)\\-(c.e+d.g)&a.e+b.g\end{array}\right]

A^{-1}=\frac{1}{a.d-b.c} \left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right]

B^{-1}=\frac{1}{e.h-f.g} \left[\begin{array}{ccc}h&-f\\-g&e\end{array}\right]

B^{-1}A^{-1}=\frac{1}{(a.e+b.g)(c.f+d.h)-(a.f+b.h)(c.e+d.g)}\left[\begin{array}{ccc}c.f+d.h&-(a.f+b.h)\\-(c.e+d.g)&a.e+b.g\end{array}\right]

So it is proved that the results are same.

b) Now, let's prove it for any n x n matrix.

(AB)(AB)^{-1}=I\\\\A^{-1}(AB)(AB)^{-1}=A^{-1}I\\\\IB(AB)^{=1}=A^{-1}I\\\\B(AB)^{=1}=A^{-1}\\\\B^{-1}B(AB)^{=1}=B^{-1}A^{-1}\\\\I(AB)^{=1}=B^{-1}A^{-1}\\\\(AB)^{=1}=B^{-1}A^{-1}

8 0
3 years ago
John runs a computer software store. Yesterday he counted 121 people who walked by the store, 56 of whom came into the store. Of
Andrej [43]

Answer:

a) 0.46; b) 0.41; c) 0.19; d) 0.59

Step-by-step explanation:

For part a,

There were 121 people that walked by; out of these 56 entered the store.  This is an empirical probability of

56/121 ≈ 0.46

For part b,

There were 56 people that entered the store.  Of those, 23 bought something.  This is an empirical probability of

23/56 ≈ 0.41.

For part c,

We multiply the probability that someone walking by enters the store and the probability that someone entering the store buys something:

0.46(0.41) = 0.1886 ≈ 0.19

For part d,

Since the probability of someone entering the store buying something is 0.41, this means the probability that this person does not buy something is

1-0.41 = 0.59.

6 0
3 years ago
Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X
timama [110]

Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)

From the image, arc WZ = 175° and arc XZ = 105°

Thus;

∠XYZ = ½(175 - 105)

∠XYZ = ½(70)

∠XYZ = 35°

5 0
3 years ago
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When Lily does a self-inventory, she lists her knowledge of Excel, her proficiency in bookkeeping, and her training in customer
Anika [276]

Answer:

The above mentioned qualities go under the category of abilities.

Step-by-step explanation:

Lily does a self-inventory to find out theat she has knowledge of Excel , proficiency in bookkeeping and training in customer service .

Ability is used to refer a person's native aptitude in a specific field.

Ability can also be trained and honed and can be made better with practice.

All of Lily's qualities mentioned come under the same above mentioned specifications. All her talents can be trained and can be bettered.

Hence her qualities come under the category of abilities.

6 0
4 years ago
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