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Rom4ik [11]
3 years ago
14

Help i will give brainliest

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

- 5x^{7}

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

Given

\frac{10x^5}{-2x^-2} ( split factors into product )

= \frac{10}{-2} × x^{5-(-2)}

= - 5x^{7}

Gre4nikov [31]3 years ago
4 0
The answer is the last one (-5x7)!
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Answer:

13

Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisector.

Hence, triangle ABE so formed would be a right triangle right angled at E.

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AB =  \sqrt{AE^2 + BE^2 }  \\  \\  \therefore \: AB =  \sqrt{5^2 + 12^2 }  \\  \\  =  \sqrt{25 + 144}  \\  \\  =  \sqrt{169}  \\  \huge \red { \boxed{ \therefore \: AB= 13}}

8 0
3 years ago
The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
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3 years ago
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Answer:

D is the answer of the question

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