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Juli2301 [7.4K]
4 years ago
11

a family has a garden in their backyard in the shape of a rectangle they want to put a fence around the garden the long side mea

sures 35 feet and the short side measures 12 feet how much Benson do they have to buy
Mathematics
1 answer:
kykrilka [37]4 years ago
5 0

Since the question is related to fencing, that is, the total length of the rectangular garden , so we need to check out the perimeter of the garden .

ANd perimeter of rectangle = 2(length + width)

Here the sides are 35 feet and 25 feet

So perimeter = 2(12+35) =2*47=94 feet .

So they have to buy 94 feet Benson .

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The Thundering Herd, an amusement park ride, is not open to patrons less than 54" tall. If the mean height of park patrons is 68
just olya [345]

Answer:

Step-by-step explanation:

Let X be the mean height of peak patrons,

Then X is normal with mean = 68 inches and std dev = 12 inches

Whenever x<54, they are not allowed to use the ride.

x=54 means z=

The z for 54" is \frac{54 - 68}{12} =-1.17

From std normal table we find that the area to the left of -1.17 is

0.3790

P(X>54) =1-0.3790

=0.6210=62.10%

P(54<x<68) = 0.5-0.3790 =0.121=12.1%

P(X>68) =0.5%=50%

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3 years ago
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Anon25 [30]
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Please help math finals!!!What is the equation of the line that has a slope of 14 and goes through the point (8,−3)
katovenus [111]

I'm taking the same final test.

The answer is y= 1/4x - 5

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Substituting it with the given point (8, -3) and the slope 1/4

it'll look like -3 = 1/4 (8) + b

Next we solve.

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A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked
kogti [31]

A) The probability of picking a white tie 300 times = (\frac{1}{8}) ^{300}

B)  The probability of picking a blue tie 300 times = (\frac{1}{8}) ^{300}

C) The probability of picking a red tie 300 times = (\frac{1}{4}) ^{300}

D) the probability of picking a black tie 300 times = (\frac{3}{8}) ^{300}

E ) the probability of picking a maroon tie 300 times = (\frac{1}{8}) ^{300}

F) the probability of NOT picking a white tie 300 times = (\frac{7}{8}) ^{300}

Step-by-step explanation:

Here, the total number of black neckties  = 6

The total number of white neckties  = 2

The total number of red neckties  = 4

The total number of maroon neckties  = 2

The total number of blue neckties  = 2

The number of times the experiment is repeated = 300

A )  P(Picking a white tie)  = \frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}

= \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = (\frac{1}{8}) ^{300}

B) P(Picking a BLUE  tie)  = \frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = (\frac{1}{8}) ^{300}

C) P(Picking a Red  tie)  = \frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16}  = \frac{1}{4}

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = (\frac{1}{4}) ^{300}

D) P(Picking a Black  tie)  = \frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16}  = \frac{3}{8}

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = (\frac{3}{8}) ^{300}

E) P(Picking a maroon  tie)  = \frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = (\frac{1}{8}) ^{300}

F) P(Picking a NOT whiten  tie)  = 1 - P( picking a white tie)

= 1-(\frac{1}{8} ) = \frac{8-1}{8}  = (\frac{7}{8} )

So, the probability of NOT  picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = (\frac{7}{8}) ^{300}

4 0
3 years ago
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