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tankabanditka [31]

3 years ago

15

if a cone and a cylinder have the same radius and the perpendicular height of the cone is twice that of a cylinder find the rati

o of the volume

2 answers:

kykrilka [37]3 years ago

7 0

Answer:

2/3

Step-by-step explanation:

h = height of the cone

Vcone = πr²h/3

H = h/2 = height of the cylinder

Vcylinder = πr²H = πr²h/2

Vcone/Vcylinder = (πr²h/3)/(πr²h/2)

= πr²h/3 x 2/πr²h

= 2/3

laila [671]3 years ago

7 0

Answer:

2/3

Step-by-step explanation:

h = height of the cone

Vcone = πr²h/3

H = h/2 = height of the cylinder

Vcylinder = πr²H = πr²h/2

Vcone/Vcylinder = (πr²h/3)/(πr²h/2)

= πr²h/3 x 2/πr²h

= 2/3

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Jennifer started out with 8 dollars. Then she got some more money for her birthday she ended up with 15 dollars. How much did sh

Aleks04 [339]

Answer: $7

Step by step explanation: so first, we have to form any equation to show that some amount of money was added to eight dollars to get a total of fifteen dollars. Our equation becomes 8+x=15
Where eight is the origins amount, x is the amount that's added to the original amount and fifteen is the final amount.
We then move eight to the other side as a negative number
x=15-8
Therefore, x is equal to seven dollars.

8 0

3 years ago

Read 2 more answers

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

How does the rate of change vary from point to point?

Tpy6a [65]

$\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 40&32\\ 28&16\\ 16&12\\ \cline{1-2} \end{array}~\hfill \stackrel{\textit{average rate of change}}{slope} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{40}~,~\stackrel{y_1}{32})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-32}{28-40}\implies \cfrac{-16}{-12}\implies \boxed{\cfrac{4}{3}} \\\\[-0.35em] ~\dotfill$

$\bf (\stackrel{x_1}{28}~,~\stackrel{y_1}{16})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-16}{16-28}\implies \cfrac{-4}{-12}\implies \boxed{\cfrac{1}{3}}$

8 0

3 years ago

Verify x + 1⁄2 is a factor of P(x)= x2<br> + x -2

kumpel [21]

Answer:

Put p(x)=0.

Step-by-step explanation:

2x-1=0 will give x=1/2. This means, If x=1/2 is given to the polynomial p(x), it will give a zero. P(1/2)=0.

8 0

3 years ago

svet-max [94.6K]

Answer is D:
e + 5 = 3e - 11

2e = 16
e = 8

Ella is 8 years old
Jamie is 8+5 = 13 years old

6 0

3 years ago