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lakkis [162]
3 years ago
6

What are the the factors of 21x squared cause I can't find it

Mathematics
2 answers:
dem82 [27]3 years ago
6 0

Factor
7
x
7
x
out of
14
x
2
14
x
2
.
7
x
(
2
x
)
−
21
x
7
x
2
x
-
21
x
Factor
7
x
7
x
out of
−
21
x
-
21
x
.
7
x
(
2
x
)
+
7
x
(
−
3
)
7
x
2
x
+
7
x
-
3
Factor
7
x
7
x
out of
7
x
(
2
x
)
+
7
x
(
−
3
)
7
x
2
x
+
7
x
-
3
.
7
x
(
2
x
−
3
)
motikmotik3 years ago
6 0
Note: * means multiply, so 5*4 means 5 times 4

21=7*3
x squared=x*x

so factors of 21x² are 1*3*7*x*x
alll the possible ones are
1
x
x²
3
3x
3x²
7
7x
7x²
21
21x
21x²
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sweet [91]
Please, do not post more than 1 or 2 questions at a time.  Out of courtesy I will address one of your six questions here:

<span>2x + 4 = 3(x – 2) + 1

You are to solve this for x.

1) perform the multiplication:     </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms:                4+6-1 = x
3) solve for x:                              x = 11
4) check:  Is 2(11) + 4 = 3(11-2) + 1 true?
   Is 22+4 = 33-6 true?  NO.  Try again, looking for the mistake:

</span><span>2x + 4 = 3(x – 2) + 1  =>   2x + 4 = 3x - 6 + 1
                                                  4 = x - 5
                                                  9 = x

Check:  Is 2(9) + 4 = 3(9-2) + 1 true?  Is 18+4 = 22 true?  YES.
The solution to #1 is  x = 9  (answer).

Submit your other questions separately, please.

</span>
8 0
3 years ago
Pls help how do i solve for x in this equation??
evablogger [386]

Answer:

x = -2

Step-by-step explanation:

1. Square both sides
x^2 +3x + 6 = x^2
2. Subtract x^2 from both sides
3x + 6 = 0
3. Subtract 6 from both sides and divide by 3
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and 3x, 6x

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