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Furkat [3]
3 years ago
8

Who was the first priminister​

Mathematics
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

Sir Robert Walpole, who led the government of Great Britain for over twenty years from 1721

Step-by-step explanation:

good luck!

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denis23 [38]
 the answer is b because
3 0
3 years ago
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PLEASE SOLVE THE QUESTIONS (WILL MARK BRANLIEST)
mel-nik [20]

Answer:

a) 4⁻³ = 1/64 = 0.015625

b)13⁻² = 1/169 = 0.0059171598

c)(-3)⁻² = 1/-3² = 0.1111111111

Step-by-step explanation:

To solve the question above, when we have an integer ( positive or negative) that is raised to a negative power, this means the reciprocal of that integer raised to the positive power

Example:

a⁻ⁿ = 1/aⁿ

a) 4⁻³ = 1/4³

= 1/(4 × 4 × 4)

= 1/64

= 0.015625

b) 13⁻² = 1/13²

= 1/(13 × 13)

= 1/169

= 0.0059171598

c)(-3)⁻² = 1/-3²

= 1/(-3 × -3)

= 1/9

= 0.1111111111

7 0
4 years ago
Determine whether the function f(x) -1 / x^2 + x^4 is even odd or neither
kirill [66]

If f(-x) = f(x) then the function is even.

If f(-x) = -f(x) then the function is odd.

We have: f(x)=\dfrac{-1}{x^2+x^4}

calculate f(-x):

f(-x)=\dfrac{-1}{(-x)^2+(-x)^4}=\dfrac{-1}{(-1x)^2+(-1x)^4}\\\\=\dfrac{-1}{(-1)^2x^2+(-1)^4x^4}=\dfrac{-1}{1x^2+1x^4}=\dfrac{-1}{x^2+x^4}=f(x)

f(-x) = f(x), therefore your answer: The function f(x) is even.

If we have: f(x)=\dfrac{-1}{x^2}+x^4

f(-x)=\dfrac{-1}{(-x)^2}+(-x)^4=\dfrac{-1}{x^2}+x^4

f(-x) = f(x)

f(x) is even

5 0
3 years ago
The sum of Juan’s pats and Nancy’s ages is 37 years l. Juan and Nancy are the same age and pat is 7 years older than Nancy . Wha
Korvikt [17]
<span>Juan + Pats + Nancy’s = 37 years

Juan = Nancy 

</span>
5 0
4 years ago
Plz look at the picture
MAXImum [283]

Answer:

image isn't loading for me :((( can you try replying to me w the question

6 0
3 years ago
Read 2 more answers
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