Answer:
y =8
Step-by-step explanation:

N=d-2
q=n+d =>q=(d-2)=q=2d-2
25q+5n+10d=525
replace q and n with d
25(2d-2) +5(d-2)+10d=525
50d-50+5d-10+10d=525
65d=585
d=9
n=7
q=16
Answer:
21120
Step-by-step explanation:Because you take 5280 and multiply it by 4
Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

92% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Volume = 5 cm * 10 cm * 2 cm
volume = 100 cm³
massa = 700 g
Densidade = massa / volume
D = 700/100
D = 7 g / cm³