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4 years ago

23.294 to 1 decimal place

Mathematics

1 answer:

Damm [24]4 years ago

7 0

Answer:

23.3

Step-by-step explanation:

because you look at the first digit after the decimal point if rounding to one decimal place or the second digit for two decimal places

draw a vertical line to the right of the place value digit that is required

look at the next digit

if it's 5 or more, increase the previous digit by one

if it's 4 or less, keep the previous digit the same

remove any numbers to the right of the line

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Write 5 pounds for $2.49 as a unit rate. round to the nearest hundreth

pantera1 [17]

The answer is 2
.01 (i think)

6 0

3 years ago

Read 2 more answers

A construction company charges $18 per hour for debris removal, plus a one time fee for the use of the trash dumpster. the total

Wewaii [24]

One time fee for the trash dumpster is $75.

Step-by-step explanation:

Cost of debris removal = $18 per hour

Total number of hours = 8

Let,

Total number of hours = x

One time fee of trash dumpster = y

According to given statement;

18x+y=219

As we know the number of hours, therefore,

$18(8)+y=219\\144+y=219\\Subtracting\ 144\ from\ both\ sides\\144-144+y=219-144\\y=75$

One time fee for the trash dumpster is $75.

Keywords: linear equations, Subtraction

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take o

Anastaziya [24]

Answer:

the cyclists rode at 35 mph

Step-by-step explanation:

Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then

distance= speed*time

since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :

time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train

thus denoting v as the speed of the cyclists :

7/8*L / v = L / 40 mph

v = 7/8 * 40 mph = 35 mph

v= 35 mph

thus the cyclists rode at 35 mph

6 0

4 years ago

C) On Sunday, there were 28 students present in class five. 18 of them were boys and the rest were girls. If only 4 girls were a

sammy [17]

There are 14 girls in class five.

<h3>How many of the students are girls?</h3>

28 students were present in class five, such that 18 of them were boys.

The number of girls on Sunday is given by the difference:

28 - 18 = 10

And we know that 4 girls did not go to school on that day, so the total number of girls on class five is:

10 + 4 = 14

If you want to learn more about math operations:

brainly.com/question/25421984

#SPJ1

6 0

2 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2