All categories

3 years ago

Is this the correct answer?

Mathematics

1 answer:

andreev551 [17]3 years ago

6 0

Answer:

y = 3x + 5

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define variables

Slope m = 3

y-intercept b = 5

Step 2: Write linear equation

y = 3x + 5

You might be interested in

What is the solution to the inequality –2.1x + 2.9 > 15.5?

Alexandra [31]

The answer is b ......

5 0

2 years ago

Read 2 more answers

13) -4= -b -1/3b and -23/3= 1/2a + 5/3a

Sergeeva-Olga [200]

-4=-1b-(1/3)b

-4=-(4/3)b

-4/-(4/3)=b

b=3

-------------------------------

(1/2)3+(5/3)2

3/6+10/6=13/6

-23/3=13/6a

(-23/3)/(13/6)=a

a=-46/13

7 0

3 years ago

An obtuse triangle has a side length of $16,$ and a side length of $21.$ The third side length is also a positive integer. How m

Ymorist [56]

Answer:

Step-by-step explanation:

3 0

3 years ago

Select all complex numbers 5-√9/4 1+√-3 4-3√-16 2-√12➗5 3+2√-9➗7 9√-7/5

harina [27]

Answer:

5-√9/4 4-3√-16 3+2√-9➗7

Step-by-step explanation:

5 0

3 years ago

$5 PAYPAL + BRAINLIEST TO ANSWER THS

expeople1 [14]

Answer:

Quadratic Equation:

$3x^2=2x +5$

$\text{Standard Form: } 3x^2-2x-5=0$

From the standard form of a Quadratic Function, we get:

$a=3,\:b=-2,\:c=-5$

Discriminant:

$\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)$

$\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5$

$\Delta=64$

From the discriminant, we conclude that the equation will have two real solutions.

State that:

$b^2-4ac$

$b^2-4ac =0:\text{The equation has 1 real solution}$

$b^2-4ac >0:\text{The equation has 2 real solutions}$

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}$

$x_{2}=\frac{-6}{6} =-1$

5 0

3 years ago