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3 years ago

What’s the correct volume ?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

7 0

Answer:

V = 12π

Step-by-step explanation:

Given radius of cone, r = 3 and y = 5

by Pythagorean theorem (or by recognizing that this is a standard 3-4-5 right triangle), we can determine that height of cone, x = 4 in

volume of cone is given by :

V= (1/3) πr²x

= (1/3) x π x 3² x 4

V = 12π

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An algebraic equation is an equation that includes: A. No variables B. Only one variable C. One or more variables D.Just numbers

shutvik [7]

Answer:

Step-by-step explanation:

Edge2020

3 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago

ASAP!! (12y + 8) (5y + 2) 2x st (sy

VladimirAG [237]

Answer:

y = 10

x = 64

Step-by-step explanation:

the equations containing y are adjacent angles in a parallelogram, meaning that they are supplementary, so we can create an equation:

5y + 2 + 12y + 8 = 180

solve this to get y = 10

the equation for x would be 2x + 5y + 8 = 180 because these angles are also supplementary

solve this to get x = 64

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3 years ago

Approximately 4% of silicon wafers produced by a manufacturer have fewer than two large flaws. If Y, the number of flaws per waf

Doss [256]

Y ~ Po (λ)

P(Y < 2) = P(Y ≤ 1) = 0.04

Plug into the pdf for Po(λ), and solve for λ

After that, use your answer to find P(Y > 5)

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3 years ago

Find the value of the following expression:<br><br> (2^8 • 5^–5 • 19^0)^–2 • (5^-2/2^3)^4 • 2^28

Maru [420]

The value of the expression is 25

3 0

3 years ago