The answer to your question is b
Answer:
A,B,D
Step-by-step explanation:
Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:


As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute 


To find the minimum of this function, we can take the first derivative, and set it to 0



![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)

Hello!
Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards
15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333
Multiply these to find the volume
5 * 5 * 0.08333 = 2.08325
Multiply this by the cost
2.08325 * 46 = 95.83
The answer is C) $95.83
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Question 2
You have to find the volume of the first pyramid
The equation we use is

V is volume
l is length
w is width
h is height
Put in the values we know

Multiply

Divide
V = 2389.3333
Now we use this to find the side length of the second pyramid

Multiply both sides by 3
<span>7167.999 = lw * 112
</span>
Divide both sides by 112
63.9999 = lw
Since it is a square pyramid we know that sides are equal
63.999 = l^2
Take the square root of both sides
8 = l
The answer is B) 8in
Hope this helps!