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andrey2020 [161]
3 years ago
12

According to the diagram which way is the magnetic field pointing ?

Physics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

left

Explanation:

Andru [333]3 years ago
5 0

Left. Use right hand rule. Have hand wide open. Thumb points in direction of current.(which makes right angle with your index finger) Four fingers in direction of magnetic field and your palm should point in the direction of the force

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hen a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant
Sladkaya [172]

Answer:

Incomplete question

Complete question:

a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?

Answer: 8m/s²

Explanation:

From the statement we deduced that acceleration varies inversely with mass where force was kept constant.

Therefore,

F/m = a or F = ma

For the first statement, substituting the mass and acceleration gives:

F = 44 x 4 = 88N

Applying the force above to the second mass gives us:

a = 88/11 = 8m/s²

3 0
3 years ago
1. A soccer player kicks a soccer ball towards the goal. If she kicks it with a velocity of 24 m/s at an angle of 31 degrees abo
ruslelena [56]

Answer:

<em>The ball will go as high as 8.46 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:

\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}

The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of g=9.8 m/s^2, then:

\displaystyle h_m=\frac{24^2\cdot \sin^2 31^\circ}{2\cdot 9.8}

\displaystyle h_m=\frac{576\cdot 0.2653}{19.6}

h_m=7.80~m

The ball will go as high as 8.46 m

4 0
3 years ago
What is the difference between magnitude and intensity
MArishka [77]
The difference is intensity is assessed using a special scale and magnitude is measure of the size ( for example a earthquake)
4 0
3 years ago
An 88.0 kg passenger is inside a 1450.0 kg elevator that rises 30.0 m in exactly 1.0 minutes. How much power is needed for the e
OleMash [197]

Answer:

Explanation:

6 0
3 years ago
A rope is vibrating in such a manner that three equal-length segments are found to be vibrating up and down with 321 complete cy
kolbaska11 [484]

Answer:

<u>2.48 m</u> is the length of the rope.

Explanation:

Cycle period is 321

Time is 20 second

Wave travels at speeds = 26.4 m/s

We know that,

\text { Frequency }=\frac{1}{T} \text { (For one cycle) }

Frequency required for 321 complete cycle in 20 seconds is

\text { Frequency }(f)=\frac{321}{20}

Frequency = 16.05 hz

We know that,

\text { Wavelength }=\frac{\text { wave velocity }}{\text { frequency }}

\lambda=\frac{v}{f}

λ = wavelength, the distance between "wave crests" (m)

v = wave velocity, the "speed" that waves are moving in a direction (m/s)

f = frequency, (cycles/ or Hz)

\lambda=\frac{26,4}{16.05}

λ = 1.65 m

As per given question "length of the rope has three equal length segment"

\mathrm{Length of the rope}=\frac{3}{2} \lambda

\mathrm{Length of the rope }=\frac{3}{2} \times 1.65

\mathrm{Length of the rope}=1.5 \times 1.65

Length of the rope = 2.48 m

Therefore, length of the rope is <u>2.48 m.</u>

7 0
3 years ago
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