Plz help fast asffff!!!!!!

Need help please. Kind of confused

muminat

What you do is look at the graph and whatever that line is on then that will be your answer.

7 0

3 years ago

Read 2 more answers

Is 2 yards greater than 5 feet?

Gelneren [198K]

Hey there!

The correct answer to your question is yes.

1 yard = 3 feet

2 yards = 6 feet (since 3 x 2 = 6)

6>5

2 yards is greater.

Hope this helps you.
Have a great day!

8 0

4 years ago

Nivyana and Ana are selling their apparel to earn money for a cruise. Knitted scarves are $50 each in Mittens are $25 per pair.

Katarina [22]

Answer:

The number of knitted scarves is 10

The number of knitted mitten is 20

Step-by-step explanation:

Given as :

The cost of each knitted scarves = $50

The cost of pairs of mittens = $25

Total number of scarves and mitten bought = 30

The total money invested to pay for items = $1000

Let The number of knitted scarves = k

Let The number of mitten = m

<u>Now, According to question</u>

The total money invested to pay for items = cost of each knitted scarves × number of knitted scarves + cost of pairs of mittens × number of mitten

i.e $1000 = $50 × k + $25 × m

Or, 40 = 2 k + m

i.e 2 k + m = 40 ........A

And

Total number of scarves and mitten bought = number of knitted scarves + number of mitten

i.e k + m = 30 ...........B

Now, solving eq A and eq B

So, (2 k + m ) - ( k + m ) = 40 - 30

Or, (2 k - k) + ( m - m) = 10

Or, k + 0 = 10

∴ k = 10

So, The number of knitted scarves = k = 10

Put the value of k into eq B

∵ k + m = 30

So, m = 30 - k

or, m = 30 - 10

∴ m = 20

The number of knitted mitten = m = 20

Hence, The number of knitted scarves is 10 and The number of knitted mitten is 20 . Answer

7 0

4 years ago

Find the missing exponent.

777dan777 [17]

Answer: what missing exponent?

Step-by-step explanation:

7 0

3 years ago

We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent

Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(c) P(X = −2) = 1/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

(c) P(Y = 2) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

( X = -2 ): { X_2 = 1 , X_1 = 3 }

P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }

P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 3 / 9 ) = ( 1 / 3 )

( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

P ( X = 1 ): P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 2 ): { X_2 = 1 , X_1 = 3 }

P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

- The distribution Y = X_2,

P(Y=0) = 0

P(Y=1) = 1/3

P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0

3 years ago