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NISA [10]
3 years ago
10

742×69 show the work

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0
51,198 is the answerrr
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Perfect squares from 100 to 200
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Answer:

121, 144, 169, 196 are the perfect squares from 100 to 200

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The distance from the center of a compact disc to the edge of the disc is 6 centimeters. What is the area of the compact disc? A
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3 years ago
13. Find the vertex of f(x)=x2 -6x +8 .
Mekhanik [1.2K]

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Answer:

  a  (3,-1)

Step-by-step explanation:

The number that "completes the square" is the square of half the x-coefficient, (-6/2)^2 = 9. Rearranging the given function to include the square trinomial, we have ...

  f(x) = x^2 -6x +9 -1 . . . . . . . here, we have 8 = 9 - 1

  f(x) = (x -3)^2 -1 . . . . . . . . . . vertex form

Comparing this to the generic vertex form ...

  f(x) = (x -h)^2 +k . . . . . . . vertex at (h, k)

we see that h=3 and k=-1.

The vertex is (h, k) = (3, -1).

6 0
2 years ago
Looking left to right, is a exponential function base increasing or decreasing?
igomit [66]
Looking from left to right it is increasing
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3 years ago
Find an equation for a tangent plane z=e-x2-y2 at the point (0,0,1).
Nadya [2.5K]

Answer: equation of the tangent plane is z = 1

Step-by-step explanation:

Given equation

z = e^(-x²-y²) at point (0,0,1)

now let z = f(x,y)

Δf(x,y) = [ fx, fy ]

= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))

now

Δf (0,0) = [ 0, 0 ] = [ a, b ]

equation of the tangent plane therefore will be

z - z₀ = a(x-x₀) + b(y-y₀)

z - 1 = 0(x-0) + 0(y-0)

z - 1 = 0 + 0

z = 1

Therefore equation of the tangent plane is z = 1

7 0
2 years ago
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