742×69 show the work

Write the first six cube if natural number

valkas [14]

Answer:

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Step-by-step explanation:

6 0

3 years ago

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a collecter has 120 movie posters and 100 band posters. She wants to sell 24 movie posters but still have her poster collection

zheka24 [161]

Answer:The answer would be C, because she wants to keep the same ratio so you would have to subtract 24 from both sides.

Step-by-step explanation:

4 0

3 years ago

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if ABC is a isosceles triangle with sides(2a+b)cm, (6a+2b+1)cm and a base of 4a cm, if it's perimeter is 28 find sides

Katyanochek1 [597]

Answer:

a=1.5, b= 3

Step-by-step explanation:

sum of all sides will give us perimeter. Therefore

2a+b+6a+2b+1+4a=28

12a+3b+1=28

12a+3b=27....eqn1

since t two sides of this isosceles triangle are equal:

2a+b=4a

2a=b

$a=\frac{b}{2}$

substituting $\frac{b}{2}$ $.$ in the first equation whenever we encounter a we will have:

$12(\frac{b}{2})+3b=27\\$

6b+3b=27

9b=27

b=3

therefore $a= \frac{b}{2} =\frac{3}{2} =1\frac{1}{2} or 1.5$

7 0

2 years ago

ANALYZE A PROBLEM Describe the x-values for which (a) f is increasing (b) f is decreasing, (c) f (x) > 0 and (d) f (x) < 0

Karolina [17]

The analysis of the graph, that has x-intercepts of (0, 2), and (0, 5), we get;

a. The function increases when x > 4

b. The function decreases when x < 4

c. The function is greater than zero when x < 3, and x > 5

d. The function is less than zero when 3 < x < 5

<h3>What is a point where a function is increasing?</h3>

The location of a point where a function is increasing is where the slope of the function is larger than zero.

The description of the graph of the function are as follows;

The shape of the function = Concave upwards

The coordinates of the vertex of the function = (4, -5)

The region where the function is decreasing is from -∞ to 4

The region where the function is decreasing is therefore; x < 4

At the vertex, (4, -5), the slope of the function is zero, therefore;

Therefore, the function is increasing where x > 4

The x-intercepts are at point (0, 3) and (0, 5)

Therefore, the function is greater than zero when x < 3, and when x > 5

The function is less than zero in the range 3 < x < 5

Learn more about the graph of functions here:

brainly.com/question/16924356

#SPJ1

7 0

2 years ago

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 − 1)3, [−1, 2]

Alja [10]

Given :

$F(x)=3(x^2-1)$

To Find :

the absolute minimum and absolute maximum values of f on the given interval

[-1,2] .

Solution :

Now , getting first order differential equation and equating its equal to zero.

$\dfrac{d(3x^2-3)}{dx}=0\\\\6x=0\\x=0$

So , x=0 is critical point .

Now , coefficient of $x^2$ is positive .

Therefore , it is increasing function after x=0 .

So , min value will be at , x=0.

$Min = (0^2-1)\times 3=-3$

And maximum value will be the maximum at the x=2 because it is increasing function .

$Max=(2^2-1)\times 3=9$

Therefore , max and min value is 9 and -3 respectively .

Hence , this is the required solution .

3 0

3 years ago