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Katen [24]
3 years ago
15

The number of wolves in a wildlife preserve is estimated to have increased continually by 3% per year. If the population is now

estimated at 5,400 wolves, how many were present 10 years ago?
Mathematics
1 answer:
34kurt3 years ago
5 0
For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>

<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
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Answer:

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Step-by-step explanation:

0.037 × ? = 37

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An airline company is considering a new policy of booking as many as 191 persons on an airplane that can seat only 180. (Past st
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1.3559644*10^-^5

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From the information given we extract the following data

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Using the binomial formula for calculating probability, i.e.

P(x; N, p) = nCx * p^x *(1-p)^{N-x}

Inputting the values

P(181; 191, 0.85) = 191C181 *0.85^{181}  *(1-0.85)^{191-181} \\ P(181; 191, 0.85) = 1.3559644*10^-^5

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