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Katen [24]
3 years ago
15

The number of wolves in a wildlife preserve is estimated to have increased continually by 3% per year. If the population is now

estimated at 5,400 wolves, how many were present 10 years ago?
Mathematics
1 answer:
34kurt3 years ago
5 0
For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>

<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

{3}^{\frac{2}{3}}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's solve ~

  • \sqrt[9]{ {3}^{6} }

  • \sqrt[9]{ (3 {}^{6}) }

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  • {3}^{ \frac{2}{3}  }

The Correct option is 1st one ~

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