Farmer Gray planted 300 seeds.
To find this, you simply multiply the number of flower pots (30) by the number of seeds in each pot (10). Thus making the answer 300.
I hope this helps!
Answer:
Step-by-step explanation:
y=3+(3x/4) or y=3+(0,75x)
-3x=-9+4=-13
X+1/3 of 13 (y) =4/3
1/3 of 13 is 4.3 or 4/3
So x=0
So y=-3x+4= -3x=-9+4 & 9+4=-13
X is 0 and y is 4/3
Answer
![\int_{0}^{6}\sqrt{1+12x^4+8x^2}dx](https://tex.z-dn.net/?f=%5Cint_%7B0%7D%5E%7B6%7D%5Csqrt%7B1%2B12x%5E4%2B8x%5E2%7Ddx)
Step-by-step explanation:
We are given that
![y=\frac{1}{3}(3x^2+2)^{\frac{3}{2}}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7D%283x%5E2%2B2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D)
Interval=[0,6]
a=0 and b=6
Differentiate w.r. t x
![\frac{dy}{dx}=\frac{1}{3}(3x^2+2)^{\frac{1}{2}}\times 6x=2x(3x^2+2)^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B1%7D%7B3%7D%283x%5E2%2B2%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Ctimes%206x%3D2x%283x%5E2%2B2%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
By using the formula ;![\frac{dx^n}{dx}=nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%5En%7D%7Bdx%7D%3Dnx%5E%7Bn-1%7D)
We know that arc length of curve
![s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx](https://tex.z-dn.net/?f=s%3D%5Cint_%7Ba%7D%5E%7Bb%7D%5Csqrt%7B1%2B%28%5Cfrac%7Bdy%7D%7Bdx%7D%29%5E2%7Ddx)
Substitute the values
![s=\int_{0}^{6}\sqrt{1+(2x(3x^2+2)^{\frac{1}{2}})^2}dx](https://tex.z-dn.net/?f=s%3D%5Cint_%7B0%7D%5E%7B6%7D%5Csqrt%7B1%2B%282x%283x%5E2%2B2%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E2%7Ddx)
![s=\int_{0}^{6}\sqrt{1+4x^2(3x^2+2)}dx](https://tex.z-dn.net/?f=s%3D%5Cint_%7B0%7D%5E%7B6%7D%5Csqrt%7B1%2B4x%5E2%283x%5E2%2B2%29%7Ddx)
![s=\int_{0}^{6}\sqrt{1+12x^4+8x^2}dx](https://tex.z-dn.net/?f=s%3D%5Cint_%7B0%7D%5E%7B6%7D%5Csqrt%7B1%2B12x%5E4%2B8x%5E2%7Ddx)
Length of curve,=![s=\int_{0}^{6}\sqrt{1+12x^4+8x^2}dx](https://tex.z-dn.net/?f=s%3D%5Cint_%7B0%7D%5E%7B6%7D%5Csqrt%7B1%2B12x%5E4%2B8x%5E2%7Ddx)
Answer:
Answer is 88
Step-by-step explanation:
I just did it