You are supposed to mutipy the first two and then add it
In standard notation it would be, 758*10^6
(a+bi)(2+3i)-i=(-11+5i)(1-i)
2a+3ai+2bi+3bi²-i=-11+11i+5i-5i²
2a+(3a+2b-1)i-3b=-11+16i+5
(2a-3b)+(3a+2b-1)i=-6+16i
Therefore; we have the next system of equations:
2a-3b=-6
3a+2b-1=16
Finally, the system of equations is:
2a-3b=-6
3a+2b=17
We can solve this system of equations by reduction method
2(2a-3b=-6)
3(3a+2b=17)
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13a=39 ⇒a=39/13=3
3(2a-3b=-6)
-2(3a+2b=17)
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-13b=-52 ⇒ b=52/13=4
Answer: a=3; b=4
Answer:
11/24 cup
Step-by-step explanation:
What you would do is add 1/8 plus 1/3. To add two fractions, each much have the same denominator. In this case, you would need to multiply 1/8 into 3/24 by multiplying 1/8 by 3 on the denominator and numerator. For 1/3, multiply each the numerator and denominator by 8 getting the fraction 8/24. Now you can line up each fraction and add the numerators, keeping the denominator at 24. That answer would be 11/24. This cannot be simplified, so the answer is 11/24 cup of food.
Whenever you are confused with assignments, it is best to tell your parent to help you or teacher the next day. Hope this helps though!
