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OverLord2011 [107]
3 years ago
10

Which statement could be used to conclude that this parallelogram is a rhombus? m m m m

Mathematics
1 answer:
NeX [460]3 years ago
3 0

I didn't ask the question but the answer options are:

m<GFH=45

m<DEF=70

m<DHE=90

m<GDE=100


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722000 <br> = ×10 <br><br><br>its scientific notation help please<br>​
koban [17]

Answer:

7.22 x 10^5

Step-by-step explanation:

Remember that the decimal is always to the right of the ones place.

1. Move it one place to the left and multiply by 10 to compensate.

2. Move it two places to left and multiply by 10^2.

3. Move the decimal point three times and multiply 10^3 to compensate, and the pattern continues until you reach the very last digit, the 7.

4. Numbers after the 7 that are not zeros will be after the decimal point.

so, 7.22 x 10^5

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suppose you flip a coin twice. what is the probability that you get tails on the first flip and tail on the second flip?
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Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu
irga5000 [103]
We want to find a scalar function f(x,y) such that \nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j.
So we need to have
\dfrac{\partial f}{\partial x}=3+4xy^2
Integrating both sides with respect to x gives
f(x,y)=3x+2x^2y^2+g(y)
Differentiating with respect to y gives
\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C
So we find that
f(x,y)=3x+2x^2y^2+C
By the fundamental theorem of calculus, we then know the line integral depends only on the values of f(x,y) at the endpoints of the path. Therefore

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6
4 0
3 years ago
Which values are in the solution set of 111 = z^2 + 11 if the replacement set is {10, 12, 14, 16, 18}?
pantera1 [17]

Answer:

10

Step-by-step explanation:

Z ^2+11=111

Z ^2=100

Z=10

8 0
3 years ago
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