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3 years ago

14

A cube has a face area of 64 square centimeters. what is the volume of the cube?

2 answers:

Ad libitum [116K]3 years ago

7 0

The faces of a cube is a squar
square area=side^2
given
side area=squae area=64

64=side^2
sqrt both sides
8=side

volume =lenght times width times height
in a cube, lenght =widht =height=side=8
in this case they all equal 8

volume=8 times 8 times 8
volume=512 cubic centimeters

fredd [130]3 years ago

3 0

The face of one side of a cube is a square shape. The formula for the area of a square
A=s² where s=side length
plug in the data we know
64cm²=s²
√64cm²=s
8cm=s

The side length on the cube is 8cm

The formula for the volume of a cube is

V=s³ where s=side length
plug in the data that we know
V=8³
V=512cm³

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Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$ .

Here, a = 6, b = -24, and c = 1. Plug these in:

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}$

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$x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}$

Thus, the zeroes are: x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$ .

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