This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.
Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6
Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2
The magnitudes of the two forces are 2N and 3N, in no particular order.
Answer:
900 sq ft
Step-by-step explanation:
The area of a trapezoid is (Base 1 + Base 2) * height/2. So to plug the numbers in...
(30+60)20/2
90*20/2
1800/2
900 sq ft
Answer: <span>(x, y) → (x + 8, y – 3)
Justification:
</span>1) From the figure you can tell that the original trapezoid ABCD was translated 8 units to the right and 3 units down to yield the trapezoid A'B'C'D'.
2) Translating 8 units to the right means: x → x + 8
3) Translating 3 units down means y → y - 3
4) Therefore, the pair (x,y) is transformed into the pair (x + 8, y - 3); that is the rule (x,y) → (x + 8, y - 3)
#7 is 0.04 and it is a terminating decimal
There would approximately be 36 ordered triples