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erastova [34]
3 years ago
7

Plz help im struggling in this lesson :( What graph represents the piecewise-defined function?

Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Well im not good at this ,butt I'll tell you something. An open dot means that point is not included , soo something like y<208 would mean 208 is not included and have an open dot, butt a closed dot means the point is included, such as <_ 450. ( The line is supposed to be under < butt i don't know how to do that.)  Hope this helps

Umnica [9.8K]3 years ago
5 0

Answer:

The piecewise function is not clear, so I will represent every function in the plots.

The Top left option:

y = 3 if x ≤ 1

y = x if x > 1

Top right option:

y = 3 if x < 1

y = 1 if x ≥ 1

Bottom left option:

y = 3 if x ≤ 1

y = 1 if x > 1

Bottom right option:

y = 3 if x < 1

y = x if x ≥ 1

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5y^2+5−4−4y^2+5y^2−4x^3 −1
vredina [299]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

6 0
3 years ago
Two bowlers bowl the following number of strikes in 9 games
ehidna [41]
First, let's calculate the mean and the mean absolute deviation of the first bowler.

FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
<em>Mean = 6.222</em>
Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
<em>MAD = 1.136</em>

SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9
</span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9
<em>Mean = 7.222</em>
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
<em>MAD = 1.531
</em>

The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>

8 0
3 years ago
What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?
OLga [1]
Hello there!

How do you find the y-intercept?

Answer: To find the y-intercept, substitute in 0 for x and solve for y

y = x² + 3x + 5

y = (0)²  + 3(0) + 5

y = 0 + 0 + 5

y = 5

Thus, the correct answer is option D (0,5)

I really hope this answer is clear enough for you to understand. If you have questions about the answer, please let me know.

As always, I'm glad to be your helper this evening~!
3 0
3 years ago
Read 2 more answers
The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many
Ray Of Light [21]

Answer:

  276 4/7 ft

Step-by-step explanation:

Let r1 represent the radius of the inner circle. Then its circumference in feet is ...

  C = 2πr

  66 = 2π(r1)

If the radius of the outer circle is (r1 +44), then its circumference is ...

  C = 2π(r1 +44) = 2π(r1) +2π(44)

  C = 66 +88π

Then the difference in the circumferences is ...

  (66 +88π) - (66) = 88π

Using the given value of π, the difference in circumferences is ...

  (88 ft)(22/7) = 1936/7 ft = 276 4/7 ft

6 0
3 years ago
What is<br><br>(\frac{-7c}{p3})^-4[/tex] <br><br>without negative exponents
ycow [4]
Can you take a pic of it because it shows as copy and paste
5 0
3 years ago
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