length of pipe= 30m
Inside dia. = 1.2m
Outside dia. = 1.8m
Volume of concrete= (outside dia. - inside dia.)h
V= (pi)
v= [(3.14*0.9*0.9)-(3.14*0.6*0.6)]30
v= (3.3534-1.1304)30
v=(2.233)30 = 66.690m cube
since it's volume the answer 66.690 is in cubic meters.
Answer:
30 and 3.4641
Step-by-step explanation:
The mean of a binomial distribution is:
μ = np
And the standard deviation of a binomial distribution is:
σ = √(npq)
Here, n = 50, p = 0.60, and q = 0.40.
μ = np = 50 × 0.60 = 30
σ = √(npq) = √(50 × 0.60 × 0.40) = 3.4641
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
