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DaniilM [7]
3 years ago
6

Kiki works in a furniture store. Her base salary is $150 per day, plus 8 percent commission on her sales. She sells several high

-priced items. table What is the total amount she earned over these three days?
Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

614

Step-by-step explanation:

614 can also look like this ^!$ if you hold down caps.

Maurinko [17]3 years ago
5 0

Answer:

Hello!!! erz here ^^

Step-by-step explanation:

The total amount should be... 614

Hope this helps!! :D

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Josh has some nickels. He says they are worth exactly 33 cents. Can you tell if Josh is correct or not?
Katyanochek1 [597]

Answer: Josh is incorrect because nickels are worth 5 cents each and 33 can not be divided by 5 exactly.

8 0
3 years ago
Graph the equation: x = y^2 - 2
Lesechka [4]
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get 
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)

for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y 
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)

then plot the points on the graph
5 0
3 years ago
What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?
DedPeter [7]
  f(x) = 112 - kx
 f(-3) = 112 - k(-3)
 f(-3) = 112 - (-3k)
 f(-3) = 112 + 3k
  121 = 112 + 3k
- 112  - 112
      9 = 3k
      3     3
      3 = k
6 0
2 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
2 years ago
Read 2 more answers
14/38 simplified? Thanks!
ira [324]
14/38 simplified would be 7/19
5 0
3 years ago
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