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andrew-mc [135]
3 years ago
12

Name the two solutions of (2x – 1)^2 = 25.

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

Solution given:

(2x – 1)^2 = 25.

square root on both side

\sqrt{(2x-1)²}=\sqrt{25}

2x-1=±5

Taking positive

2x-1=+5

2x=+5+1

x=6/2=3

Taking negative

2x-1=-5

2x=-5+1

x=-4/2

x=-2

<u>T</u><u>h</u><u>e</u><u> </u>two<u> </u><u>Solution</u><u> </u><u>i</u><u>s</u><u> </u><u>x</u><u>=</u><u>-</u><u>2</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u>=</u><u>3</u><u>.</u>

Westkost [7]3 years ago
6 0

Answer:

3 & -2

Step-by-step explanation:

(2x – 1)^2 = 25

2x -1 = ±√25

2x -1 = ± 5

• 2x = 5+1

2x = 6

x = 3

• 2x = -5+1

2x = -4

x = -2

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