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Gwar [14]
3 years ago
5

What is a straight path that has a beginning but not an ending

Mathematics
1 answer:
ohaa [14]3 years ago
7 0
The answer is a Ray.
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NAME THE LARGEST ANGLE <br><br> NAME THE SMALLEST ANGLE
Natasha2012 [34]

Answer:

largest: cu smallest: rc

5 0
2 years ago
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Someone answer and do t try to take my points please. What do the Greeks and Romans have in common (similarities) in terms of th
stellarik [79]

Answer:

they are both polytheistic religions.

4 0
3 years ago
For which value of theta is sine theta = negative 1?
Ivan

Answer:

1) 270 degrees

2)  pi/4 rad

Step-by-step explanation:

1.) For which value of theta is sine theta = negative 1?

Given

sintheta = -1

theta = arcsin(-1)

theta = -90degrees

Since sin is negative in the third and 4th quadrant

In the third quadrant, theta = 180 + 90 = 270degrees

In the fourth quadrant, theta = 360 - 90 = 270 degrees

Hence the required value of theta is 270degrees

2) Given the radius of the circle to be 1, the y axis value will also be 1 units

Opposite = 1

adjacent = 1

hyp = √1²+1²

hyp = √2

sin theta = opp/hyp

sin theta = 1/√2

theta = arccsin(1/√2)

theta = 45 degrees

Express in radians

45 degrees = pi/4 radians

Hence the required angle in the first quadrant is pi/4 rad

4 0
2 years ago
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A student performed the following steps to find the solution to the equation x^2 + 14x + 40 = 0. Where did the student go wrong?
Alja [10]

Answer:

A. in Step 3

Step-by-step explanation:

It is factored correctly. Then separated into two smaller equations correctly. But in solving x + 10 = 0, there is an error.

x + 10 = 0

Add -10 to both sides.

x = -10

So, the error is in step 3.

3 0
2 years ago
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Pls Help!!! Worth 99 Pts!!
Sladkaya [172]

Answer:

First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)

To find the zeros, you set the equation equal to 0 and solve for x

x^3+2x^2-8x=0

x(x^2+2x-8)=0

x(x+4)(x-2)=0

x=0   x=-4   x=2

So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)

And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.

Plugging in a -5 gets us -35

-1 gets us 9

1 gets us -5

3 gets us 21

So now you know end behavior, zeroes, and signs of intervals

Hope this helps

5 0
2 years ago
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