Can someone help me pleaseee, and quick!

Mathematics

1 answer:

siniylev [52]4 years ago

7 0

Answer:

AB ≈ 7.10

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos65° = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{3}{AB}$

Multiply both sides by AB

AB × cos65° = 3 ( divide both sides by cos65° )

AB = $\frac{3}{cos65}$ ≈ 7.10 ( to the nearest hundredth )

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In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A

AURORKA [14]

Answer:

$A = \dfrac{C^2}{4\pi}$

Step-by-step explanation:

Given that

Area of a circle $A=\pi r^2$

Circumference of the circle $C = 2 \pi r$

Let us re-write the equation of area of circle:

$A=\pi r^2$

$A = \pi \times r \times r$

Multiplying and dividing with 2:

$A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}$