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Vadim26 [7]
3 years ago
7

For the spring festival, the Math Club is selling rulers for $1 and compasses for $2.50. the club would like to sell as many ite

ms as they can to raise funds. they need to at least make $15 to break even. write an inequality to represent this situation. let r=#of rulers sold and c=#of compasses sold.... School rules state that the club can sell a maximum of items for the festival. Write another inequality for this constraint (limitation).
Mathematics
1 answer:
blagie [28]3 years ago
5 0
9 rules and 6 compasses (2.50×2=6) (1×9=9) (6+9=15)
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denis-greek [22]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -3x - 2

5x + 2y = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     5x + 2(-3x - 2) = 15
  2. Distribute 2:                          5x - 6x - 4 = 15
  3. Combine like terms:            -x - 4 = 15
  4. Isolate <em>x</em> term:                      -x = 19
  5. Isolate <em>x</em>:                               x = -19

<u>Step 3: Solve for </u><em><u>y</u></em>

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  2. Substitute in <em>x</em>:                                     y = -3(-19) - 2
  3. Multiply:                                                y = 57 - 2
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romanna [79]

Answer:

<u>The original number is 96.875</u>

Step-by-step explanation:

Let's find the original number using the Direct Rule of Three, this way:

       Percentage          Number

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96x = 93 * 100

96x = 9,300

x = 9,300/96

x = 96.875

<u>The original number is 96.875</u>

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