Since you know:
c = 30 substitute/plug it into the equation
Plug in 30 for "c" in the equation
f = 54 + 32
f = 86 (86°F if you need to add units)
X = -2 or lesser than that
So x = < -2
The team gained a total of 3 yards. That is because they first gained 8 (0 + 8), then lost 3 (8 - 3).
Let x = 78.3
y = 87.2
σₓ = 5.6 and σ₍y₎ = 6.3
number of pieces n = 50
z = z-score value =1.96 in this case
<span> A 100(1-α)%
confidence interval for the difference in large sample means is:
(x – y) ± z x </span>√( σₓ² / n+ σ₍y₎²<span>/n)
by putting the values,
=(78.3-87.2) </span>± 1.96 x √(5.6² /50 + 6.3² /50)<span>
</span><span>= -8.9 ± 2.34
</span><span>= [-11.24, -6.56]</span>