2x-7y=18 _(1)
-2x+4y=5
11y=23 , Y=23/11 sub in 1
2x-7×23/11=18
2x = 18×11 + 7×23
x = ( 198 + 161 )/2 = 359/2
Answer:
14.
let me know if you want the steps
Answer:
Step-by-step explanation:
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7√(x²) 7√(x²)
------------- = ----------------------
5 √(y³) 5√( y^(3/2) )
We want to get the fractional exponent out of the denominator. To do this, multiply both numerator and denominator by y^(1/2):
7√(x²) 7√(x²) y^(1/2) 7√(x²)·y^(1/2) 7x√y
------------- = --------------------- * ----------- = --------------------- = ----------
5 √(y³) 5√( y^(3/2) ) y^(1/2) 5 √(y²) 5y
This is the final answer. We have succeeded in removing radicals / fractional exponents from the denominator.
