Um not really a specific enough question for a good answer, but I'll give it a go
all you have to do is use long division and divide the numerator by the denominator (top by bottom)
most often the result will not be pretty so round appropriately (i recommend tenths or hundredths)
for exampe
25/11
use some handy division skills, and you'll get about 2.27
note that improper fractions mean that the decimal form will always be greater than 1, or less than -1
The sum of all the angles in a triangle is 180°.
There is a right angle -> a 90° angle on the hypotenuse of the largest triangle (the largest being the one that contains both smaller triangles)
To solve this problem, you don't really need to solve y.
Next to the 48° angle, you have two of the same angles, both x variables.
The sum of these three angles has to be 180°

Now that we have x, we can calculate the value of z.
We add the value of x and the 90° angle, we later subtract it from 180°
Calculating the value of z:

If you really want to know the value of y, you just add up the 90° angle and the 48°, then subtract that from 180°
a. factor A = x^2 -30x + 225 = (x - 15)(x - 15)
side length =<u> (x - 15)</u>
b. add (x - 15) four times = 4(x - 15) =<u> 4x - 60</u>
Answer:
a quadrilateral is a polygon with 4 sides and for corners
Step-by-step explanation:
Answer:
Triangle 2
Step-by-step explanation:
That is Pythagorean Theorem, which is only for right triangles. The second triangle has the little square, so you know it is 90 degrees.