Answer:
4 mm
Step-by-step explanation:
= 4
So, the answer is 4 mm.
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Simplify both sides of your equation.
Subtract 4 from both sides.
Multiply both sides by 2(-1).
m = -12
Answer:
The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 34
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0322
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 134 - 5.84 = 128.16 calories
The upper end of the interval is the sample mean added to M. So it is 134 + 5.84 = 139.84 calories
The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.
Answer:−3+3=−4
2+3−=15
4−3−=19
2 3
Step 1: Pair the equations to eliminate y because the y terms are already additive inverses
1
−3+3=−4
2+3−=15
2
2+3−=15
4−3−=19
2 3 4
3 =11
5
6 −2=34
Step 2: Write the two new equations
as a system
Step 3: Substitute the value for x and z
into one of the original equations
3 =11
3 5 +2=11
4
5−3+3 −2 =−4
15+2=11
5
6 −2=34
5−3−6=−4
−3−1=−4
9x
2=−4
=−2
= 45
x = 5
−3=−3
=1
The solution (5, 1, -2)
Step-by-step explanation:
The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.