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balandron [24]
3 years ago
15

Write an integer whose absolute value is greater than itself.

Mathematics
1 answer:
Fed [463]3 years ago
8 0
<span>The set of an integer is called the set Z
The set of integers number is composed by the positive whole number {0, 1, 2, 3…} and the negative whole number {…-4, -3, -2, -1, 0} .We write it as follow Z= {…- 4, -3, -2, -1, 0}U{0, 1, 2, 3…}. If we assume that k is inside Z, so k can be a negative integer of positive integer. Besides the absolute value of a number is always the positive value of this number. Let be k<0 an integer different from zero, so abs(k) >0, and abs(k)> k for all value of k. For example for k= -2, and abs(k)=abs(-2)=2> -2 (always)</span>
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1/3 times 1/5 simplified
matrenka [14]
1/3 times 1/5 equals 1/15. That is already simplified :).
8 0
3 years ago
Read 2 more answers
Explain why their are no solutions to the system of inequalities <br> y ≤2x-5 <br> y ≥2x+1
rosijanka [135]

Answer:

Sorry this is late and I think this is right.

They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.

For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:

<em>y < - 1/2x -3</em>

<em>y > 1/2x + 2</em>

<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.

I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.

7 0
3 years ago
What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

4 0
3 years ago
Answer right = get brainliest
saw5 [17]

Answer:

i believe u add all of them up

Step-by-step explanation:

3 0
3 years ago
Which of the following represents the factorization of the trinomal below
Allisa [31]
I believe B. is your answer. If you use the ac method, you will multiply 8 and 3 which is 24. So now, what factors of 24 will give you 10?6 and 4

Now substitute

8 {x}^{2}  + 4x + 6x + 3
Now do factorization by grouping.

4x(2x + 1) + 3(2x + 1)
Therefore, your answer is (4x+3)2x+1)
6 0
3 years ago
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