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alina1380 [7]
3 years ago
15

Y=x2 +6x-2

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = x² + 6x - 2

To complete the square

add/ subtract ( half the coefficient of the x- term )² to x² + 6x

y = x² + 2(3)x + 9 - 9 - 2

  = (x + 3)² - 11 ← in vertex form

with (h, k) = (- 3, - 11 )

Turning point = (- 3, - 11 )

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Amy has to write a paper for school that has more than 2,878 words. She has already written 1,037 words and writes at a rate
densk [106]

Answer:

C

Step-by-step explanation:

263x = words per day

add on 1,037 because she already wrote them

263x + 1,037 > 2,878

7 0
3 years ago
Need help with geometry. Finding the slant height of a pyramid
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Write the first four terms of the sequence. rule start at 5 1/2, add 1 1/5
Hitman42 [59]

Answer:

5\frac{1}{2},6\frac{7}{10},7\frac{9}{10},9\frac{1}{10}

Step-by-step explanation:

The first term of the sequence is

a_1=5\frac{1}{2}

To find the second term add 1\frac{1}{5} to the first term;

a_2=5\frac{1}{2}+1\frac{1}{5}=6\frac{7}{10}

To find the third term add 1\frac{1}{5} to the second term;

a_3=6\frac{7}{10}+1\frac{1}{5}=7\frac{9}{10}

To find the fourth term add 1\frac{1}{5} to the third term;

a_4=7\frac{9}{10}+1\frac{1}{5}=9\frac{1}{10}

The first four terms are

5\frac{1}{2},6\frac{7}{10},7\frac{9}{10},9\frac{1}{10}

7 0
3 years ago
Step 1: Choose ONE of the following triangles and complete the table below:
Archy [21]

The question is incomplete below you will find the missing part.

Step 1 : Choose ONE of the following triangles complete the table below:

1. Obtuse Scalene Triangle Translation to prove SSS Congruence

or

2. Isosceles Right Triangle Reflection to prove ASA Congruence

or

3. Equilateral Equiangular Triangle Rotation to prove SAS Congruence

Original Coordinate Point

Transformation Rule

Image Coordinate Points

A (1, 4)      (x,y) -> (x+ ,y -)      A’ ( , )

B ( 7,4)     (x,y) -> (x+ ,y - )     B’ ( , )

C (8,9)      (x,y) -> (x+ ,y -)     C’ ( , )

The appropriate table is also shown below.

The triangles ABC and A'B'C' are congruent by SSS through Obtuse Scalene Triangle Translation  because the corresponding sides are congruent

Two triangles are congruent if their size and shape are the same.

Now we have to transform the triangle,

The coordinates of the triangle ΔABC are given as:

A = (1, 4)

B = (7,4)

C = (8,9)

so the lengths of the sides of the triangle are given by

AB= √(7-1)²+(4-4)²= √6²= 6

BC= √(8-7)²+(9-4)²= √1²+5²= √1+25= √26

CA= √(8-1)²+(9-4)²= √7²+5²= √49+25= √74

In order to prove the SSS congruence, we have to transform the triangles under the following translation rule:

(x,y) -> (x -3, y +6)

in the above translation,

The triangle will be translated 3 units left

And then translated 6 units up.

So, we have the new coordination of the points of the translated triangle ΔA'B'C'

A' = (1-3, 4+6)

A' = (-2, 10)

B' = (7-3, 4+6)

B' = (4, 10)

C' = (8-3, 9+6)

C' = (5, 15)

Now

so the lengths of the sides of the triangle are given by

A'B'= √(4-(-2))²+(10-10)²= √6²= 6

B'C'= √(5-4)²+(15-10)²= √1²+5²= √1+25= √26

C'A'= √(-2-5)²+(10-15)²= √(-7)²+(-5)²= √49+25= √74

By comparing two triangles ΔABC and ΔA'B'C'

AB ≅ A'B'

BC ≅ B'C'

CA ≅ C'A'

Hence ΔABC ≅ A'B'C' (By S-S-S rule)

By the above transformation, the triangles ABC and A'B'C' are congruent by SSS because the corresponding sides are congruent as all the points are gone through the same transformation.

Learn more about the transformation

here: brainly.com/question/4289712

#SPJ10

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