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Lapatulllka [165]
3 years ago
5

Which of the following terms best describes an exponent that has the forn m/n where m and n are integers? A. Complex number B. R

ational Equation C. rational Exponent D. Like Radicals
Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer with explanation:

A number of the form ,\frac{m}{n},  where m and n are integers are called Rational number when, n≠0.

Let, ,p=\frac{m}{n},

Then Exponent Raised to power, , that is ,\frac{m}{n},

 (\text{Exponent})^{\text{Rational}}=e^{\frac{m}{n}}=e^p

 Option C: Rational Exponent

vredina [299]3 years ago
3 0
C. a rational exponent because m/n is a rational equation and is an exponent in this case
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7nadin3 [17]

Answer:

68

Step-by-step explanation:

1) Plug In (when you plug in you replace the defined variable with the number given. usually you have to find the numbers to plug in but since they're already given to you you just plug them in.) 4(3) + 8(7)=T   T= total cost

2) Multiply 4*3=12 8*7=56

3) Add 12+56=68

4) <u>T=68</u>

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3 years ago
Quadrilateral ABCD is reflected across the x -axis. What are the coordinates of quadrilateral A'B'C'D'? A. A' (5, –5), B' (1, –5
Yuki888 [10]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Simplify the expression x8 y-26/x14 y-5 X x-39 y-21.
KonstantinChe [14]
\frac{x^8y^{-26}}{x^{14}y^{-5}}[x^{-36}y^{-21}]

We will apply these following power rule

x^m*x^n = x^{m+n}
x^m/x^n=x^{m-n}

[ \frac{x^8}{x^{14}}][ \frac{y^{-26}}{y^{-5}}][x^{-39}y^{-21}]
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8 0
4 years ago
Please help will give medal!!!!
shepuryov [24]
If you are given with all the tree sides of the triangle, you may solve for all the angles through the Law of Cosines,
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7 0
4 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
4 years ago
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