Write a system of equations with (4,-5) as its solution

Mathematics

1 answer:

leonid [27]4 years ago

8 0

Answer:

Step-by-step explanation:

I would start by choosing my coefficients for the 2 equations. I will choose 1 and 2 for the first equation and 3 and 4 for the second equation.

1x + 2y = ?

3x + 4y = ?

Now I need to figure what in on the right-hand side, so I would substitute in 4 for x and -5 for y.

1(4) + 2(-5) = 4 - 10 = -6, so my first equation would be x + 2y = -6

3(4) + 4(-5) = 12 - 20 = -8, and my second equation is 3x + 4y = -8

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katrin2010 [14]

$\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}$

$Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}$

7 0

3 years ago

What is the square root of 248 + square root of 63

enyata [817]

Answer:

1) √248 = ± 15.7480157

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Step-by-step explanation:

7 0

3 years ago

Tori uses the greatest common factor and the distributive property to rewrite this sum:

vovikov84 [41]