Answer:
b. (3,3)
Step-by-step explanation:
Answer:
1.) f(x) = x*x - 7x + 10
2.) f(x) = x*x - 5x
3.) f(x) = 4*x*x - 5x - 6
4.) f(x) = 6*x*x -5x + 1
Step-by-step explanation:
1.) 2 and 5 (x -2)(x - 5) = f(x) = x*x - 7x + 10
2.) 0 and 5 f(x) = x*(x -5) = x*x - 5x
3.) -3/4 and 2 (x + 3/4)(x -2) = x*x - (5/4) x - 3/2,
need integers f(x) = 4xx - 5x - 6
4.) 1/2 and 1/3 (x - 1/2)(x - 1/3) = f(x)
x*x - 1/3 x - 1/2 x + 1/6
xx - 5/6 x + 1/6
6 xx - 5x + 1
Answer:
Step-by-step explanation:
By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that
f'(c) = [f(6) - f(1)]/ (6 - 1)
So, f(6) - f(1) = 5f'(c).
Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20
So, f(6) - f(1) is between 10 and 20.
160/3 is 53 1/3 as a fraction
I know this but I can't remember how to do the process.
