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Dmitry [639]
3 years ago
6

ALGEBRA HELP !!!!! Which of the following is the simplest form of this expression? —photo attached

Mathematics
1 answer:
sasho [114]3 years ago
4 0

\displaystyle \frac{ \sqrt[5]{a^4}}{ \sqrt[3]{a^2}}= \frac{a^{\frac{4}{5}}}{a^{\frac{2}{3}}}=a^{\frac{4}{5}- \frac{2}{3}}=a^{\frac{12-10}{15}}=\boxed{a^{\frac{2}{15}}}

Answer is: A. a^(2/15)

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An invoice quotes a price of $620 subject to discounts of 30%, 15%, and 5%. What is the selling price? (Round off your answer to
Eddi Din [679]
Selling price=620(1-0.30)(1-0.15)(1-0.05)
selling price = 620(.7)(.85)(.95) = 350.46
8 0
3 years ago
Which graph represents an odd function?
Nookie1986 [14]

Answer:

<h2>The first graph in the second image is an odd function.</h2>

Step-by-step explanation:

An odd function has a graph that it's symmetric about the origin, that is, the origin is like a mirror. In other words, the graph of an odd function has a specific symmetry about the origin.

So, we have to look for those graph that has symmetrical points in opposite quadrants, I and III or II and IV.

You can observe that the first graph of the second image has this behaviour. You can see that the points are symmetrical across the origin. If you graph a line defined as y=-x, you will observe that such line acts like a mirror.

Therefore, the odd function is the first graph in the second image.

8 0
3 years ago
Read 2 more answers
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
HELP QUICK! which graph represents the solution set for the inequality PICTURE INCLUDED
grandymaker [24]
The answer is C because it equals 9
5 0
2 years ago
Estimate then find the difference or sum <br><br> 86+17
kumpel [21]
Estimation for addition: 86 rounds up to 90 and 17 rounds up to 20 so:
90 + 20 = 110
Estimation for subtraction is the same thing but with subtraction
90 - 20 = 70

Now for the exact answers:
86 + 17 = 103
86 - 17 = 69

Your answers are 110, 70, 103, and 69.

8 0
2 years ago
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