Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5,
2 answers:
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Answer:
The Length of third side is 52 units.
Step-by-step explanation:
Given:
Length of First side = 48
Length of second side = 20
Also given the angle between them is 90°.
Hence we can say figure shown is a right angled triangle.
For finding the third side we can use Pythagoras theorem which states that;
"If a triangle is right angled then, the Square of the hypotenuse is equal to sum of the square of the other two sides."
Hence substituting the values we get;
Now taking Square root on both side we get;
Hence Length of Third side is 52 units.
Answer:
y = 3/4x - 5
Step-by-step explanation:
An equation of a line can be written in slope-intercept form:
y = mx + b
where m is the slope and b is the y-intercept.
Let's plug in what we know.
The slope is 3/4.
y = 3/4x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 3/4(4) + b
To find b, multiply the slope and the input of x(4)
-2 = 3 + b
Now, subtract 3 from both sides to isolate b.
-5 = b
Plug this into your standard equation.
y = 3/4x - 5
This is your equation. It has a slope of 3/4, and passes through (4, -2)
Hope this helps!
