Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5, and 6. Round the measure to the nearest whole degree.
2 answers:
We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6. a=4 , b=5, c=6 Angle 1: cosA = 5² + 6² - 4² / 2*5*6 A=41.41° Angle 2: cos B = 4²+6² -5² /2*4*6 B= 55.77° Angle C: C = 180° - 41.41° - 55.77° C = 82.82° The smallest angle is A which is equal to 41.41°.
Answer:
41
Step-by-step explanation:
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