Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5,

Question

Nataliya [291]

3 years ago

15

Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5,

and 6. Round the measure to the nearest whole degree.

Mathematics

2 answers:

Ierofanga [76] · Answer 1 · 2022-02-20T11:47:17+03:00

We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6.
a=4 , b=5, c=6
Angle 1:
cosA = 5² + 6² - 4² / 2*5*6
A=41.41°

Angle 2:
cos B = 4²+6² -5² /2*4*6
B= 55.77°

Angle C:
C = 180° - 41.41° - 55.77°
C = 82.82°

The smallest angle is A which is equal to 41.41°.

Nataly_w [17] · Answer 2 · 2022-02-20T12:48:37+03:00

Nataly_w [17]3 years ago

3 0

Answer:

41

Step-by-step explanation: