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3 years ago

8

when you use the distance formula you are building and blank whose hypotenuse connects two given points (A) parallelogram (B) ri

ght triangle (C) acute triangle or (D) trapezoid

2 answers:

Marrrta [24]3 years ago

7 0

the answer to you're question is B ; Right Triangle

Alenkasestr [34]3 years ago

3 0

The answer is B; right triangle

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Work out the percentage change to 2 decimal places when a price of £57.99 is decreased to £49.99.

IRISSAK [1]

Answer:

Percentage change in price = 13.80%

Step-by-step explanation:

Given that:

Original price = £57.99

Decreased price = £49.99

Difference = Original price - Decreased price

Difference = 57.99 - 49.99

Difference = £8.00

Percent change = $\frac{Difference}{Original\ price}100$

Percent change = $\frac{8.00}{57.99}*100$

Percent change in price = 13.80%

Hence,

Percentage change = 13.80%

5 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

Find the value of the trigonometric ratio, cos M.

Montano1993 [528]

Answer:

The answer is option D.

Step-by-step explanation:

cos M = adjacent / hypotenuse

From the picture

b is the adjacent

x is the hypotenuse

so

cos M = b/x

Hope this helps you

3 0

3 years ago

What’s the answer??(SOMEONE PLEASE HELP)

mote1985 [20]

I think it’s B. but i’m not 100% sure

7 0

3 years ago

Is this a function or no?

IgorLugansk [536]

Answer:

No

Step-by-step explanation:

Positives cannot point at negatives I think.

5 0

2 years ago