To organize the expressions according to the number of terms, you should understand what a term is. A term is either a single number or variable, or numbers and variables multiplied together. Terms are separated by + or − signs. It is organized as follows:
2x2y + x2 - 3x + 4
3x + y + z
x + 2xyz
9x2yz
There are commonly used four inequalities:
Less than = <
Greater than = >
Less than and equal = ≤
Greater than and equal = ≥
The inequalities that describe the constraints on the number of each type of hedge trimmer produced are:
x + y ≤ 200
2x + 10y ≤ 1000
<h3>What is inequality?</h3>
It shows a relationship between two numbers or two expressions.
There are commonly used four inequalities:
Less than = <
Greater than = >
Less than and equal = ≤
Greater than and equal = ≥
We have,
Total number of hours = 1000
Total number of trimmers = 200
Let x represent the number of cord-type models,
Let y represent the number of cordless models.
Now,
x + y ≤ 200
2x + 10y ≤ 1000
Thus,
The inequalities that describe the constraints on the number of each type of hedge trimmer produced are:
x + y ≤ 200
2x + 10y ≤ 1000
Learn more about inequalities here:
brainly.com/question/20383699
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Answer:
g(x) = 3x - 3
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
If a line is parallel to another, they have the same slope.
Step 1: Define variables
<em>m</em> = 3
Random pt (2, 3)
y = 3x + b
Step 2: Find <em>b</em>
3 = 3(2) + b
3 = 6 + b
b = -3
Step 3: Write parallel linear equation
y = 3x - 3
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
