60 sixth graders 40% of the sixth graders will attend.

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

I don't see a question here, but I think your asking how many sixth graders will attend. The answer is 24.

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Leah's age is twice her cow old are Leah and her cousin?usin's age. If they add their ages together they get 36. How old are Lea

nignag [31]

Okay so lets call Leah "L" and her cousin "C". We know that L+C=36 ... we also know that Leah is twice her cousins age. Therefore, L=2 times C, or L=2C. This is because Leah's age is equivalent to twice as much as her cousin's.
Now that you know that L=2C, you can plug this back into the equation. This should make it so that's there's only one variable now!
L+C=36
(2C)+C=36 ... here we subbed in L=2C
3C=36 ... we add up the C's
C=12 ... we isolate for C by dividing both sides by 3

So her cousin's age is 12 years old. Leah's age is twice that. Thus, she's 24. If you add the two up: 12+24, you indeed get 36. Hope that helps :))

4 0

3 years ago

0.5 ft<br> 0.4 ft<br> 0.8 ft<br> Area of base =

beks73 [17]

Answer:

it may can be 0.16 ft

Step-by-step explanation:

0.5 x 0.4 = 0.2

0.8 x 0.2 = 0.16

7 0

2 years ago

Read 2 more answers

Find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

Flauer [41]

Answer:

The coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

Step-by-step explanation:

We need to find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

The midpoint of line segment can be found using formula:

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We have $x_1=14, y_1=-8, x_2=12, y_2=-1$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\Midpoint=(\frac{14+12}{2},\frac{-8-1}{2})\\Midpoint=(\frac{26}{2},\frac{-9}{2})\\Midpoint=(13,\frac{-9}{2})$