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timama [110]
4 years ago
8

What is the absolute value of |x-3|=2

Mathematics
1 answer:
Norma-Jean [14]4 years ago
4 0

Answer:

5 or 1

Step-by-step explanation:

|x-3| = 2

x-3 = 2 or -2

x = 5 or 1

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Make an equation to represent the area of a square whose sides are given by the expression x + y
ki77a [65]

Answer:

x^2 + 2xy + y ^2

Step-by-step explanation:

A = a^2

a = x + y

(x + y) + (x + y)

x^2 + xy + xy + y^2

x^2 + 2xy + y ^2

4 0
3 years ago
How do you find the rate of change for graphs? For example ( see photo above )
aleksklad [387]

Answer:

Step-by-step explanation:

Take the old value - the new value. then divide that by the old value.

7 0
3 years ago
Read 2 more answers
A company manufactures tires at a cost of $40 each. The following are probabilities of defective tires in a given production run
asambeis [7]

Answer:

The expected cost of the company for a 3000 tires batch is $120255

Step-by-step explanation:

Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires  is 3000p.

Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are A_1,\dots, A_n events that partition the whole sample space, and we have a random variable X over the sample space, then

E(X) = p(A_1)E(X|A_1) + \dots + p(A_n)E(X|A_n).

So, in this case, we have the following

E(X) = P(p=0\%)E(X|p=0\%)+P(p=1\%)E(X|p=1\%)+P(p=2\%)E(X|p=2\%)+P(p=3\%)E(X|p=3\%) = 0.1\cdot 3000\cdot 0 + 0.3\cdot 3000\cdot 0.01+ 0.4\cdot 3000\cdot 0.02+ 0.2\cdot 3000\cdot 0.03 = 51.

Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.

Finally, note that the cost of the batch would be 40Y+45X. Then

E(40Y+45X) = 40E(Y)+45E(X) = 40\cdot 2949+45\cdot 51=120255

3 0
4 years ago
A, = 8 + 2(n - 1).<br><br>Dose anyone know this.​
Anna71 [15]
It is 54 because if you add a to 8 you get
5 0
3 years ago
Read 2 more answers
Ms. Smith puts a variety of wrapped
marusya05 [52]

Using the binomial distribution, it is found that the number of students that would be expected to select a gold-wrapped candy  from the bag is given by:

  • B. 5 students

The candies are chosen with replacement, which means that for each student, the probability of choosing a gold wrapped candy is independent of any other student, hence the binomial distribution is used.

<h3>What is the binomial distribution?</h3>
  • The <em>binomial distribution</em> is the <u>probability of exactly x successes on n repeated trials, with p probability of a success on each trial</u>.

The expected value of the binomial distribution is:

E(X) = np

In this problem:

  • There are 15 students, hence n = 15.
  • Of a totlal of 5 + 1 + 2 + 4 = 12 candies, 4 are gold wrapped, hence p = \frac{4}{12} = \frac{1}{3}

Then, the <em>expected value</em> is:

E(X) = np = 15\times \frac{1}{3} = 5

Hence, option B is correct.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

4 0
3 years ago
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