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abruzzese [7]
3 years ago
11

Jordy works at the block factory. he has an order to pack 3,280 blocks. how can he pack the blocks using the fewest packages

Mathematics
2 answers:
sineoko [7]3 years ago
4 0
By packing the 3280 blocks in one package?
Fynjy0 [20]3 years ago
3 0

Answer:

There are two ways in which Jordan can pack 3,280 blocks.  

Step-by-step explanation:

We are given the following information:

Number of blocks to be packed = 3,280

We have to make the following assumptions in order to answer the question:

Let us suppose that Jordan can pack the blocks in packages of 1000, 100 and 10.

Expanding 3280:

(3\times 1000) + (2\times 100) + (8\times 10) = 3000 + 200 + 80 = 3280

In order to pack, Jordan can pack 3,280 blocks in 3 packs of 1000, 2 packs of 100 and 8 packs of 10.

He could also use 3 packages of 1000 and 4 packages of 100 to use fewest packages. This packaging would have an extra space for 20 blocks.

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jekas [21]

Answer:

The amount at the end of second quarter is $1842.704

Step-by-step explanation:

Given as :

The principal in saving account = $1640

The rate of interest = 6 % compounded quarterly

The time period = 6 months

Now,<u> from compounded method</u>

The amount at the end of first quarter = A_1 = principal + 6 % of principal

I.e  A_1 = $1640 + 6 % × $1640

Or, A_1 = $1640 + $ 98.4

∴ A_1 = $1738.4

Again ,

The amount at the end of second quarter = A_2 = A_ + 6 % of  A_1

I.e  A_2 = $1738.4 + 6 % × $1738.4

Or, A_2 = $1738.4 + $104.304

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8 0
3 years ago
Trigonometry is the worst please someone answer this for me ... no links please
quester [9]

Answer:  Approximately 22.62 degrees

===============================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(y) = 12/13

y = arccos(12/13)

y = 22.6198649

y = 22.62

Notes:

  • Arccosine is the same as inverse cosine. On your calculator there should be a button labeled \cos^{-1}
  • Make sure your calculator is in degree mode
  • The decimal result for y, shown above, is approximate. I rounded to two decimal places to show the final answer. Round however you need to if your teacher instructs otherwise.
5 0
3 years ago
Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?
Natasha_Volkova [10]

Answer:

24567389+35432611 =60000000

Step-by-step explanation:

Given

24567389+35432611 =

Required

Solve

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

<em>The numbers in parentheses are carried from previous sum</em>

Start from the right

9 + 1 = 10 \to Write 0, carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                         0

8 + 1 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                       0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                   0 0 0

7+2 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                0 0 0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

             0  0 0 0 0

5 +4 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

         0  0  0 0 0 0

4 +5 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

      0  0  0  0 0 0 0

2 +3 + (1) = 6 \to Write 6

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

 6  0  0  0  0 0 0 0

Hence:

24567389+35432611 =6  0  0  0  0 0 0 0

8 0
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Hey there ! please refer to the attachment .

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